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Updated on: 27 Mar 2018, 00:54
Originally posted by yogeshagarwala on 13 Jul 2010, 14:59.
Last edited by Bunuel on 27 Mar 2018, 00:54, edited 2 times in total.
Last edited by Bunuel on 27 Mar 2018, 00:54, edited 2 times in total.
Edited the question.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
23% (01:58) correct
77%
(01:43)
wrong
based on 391
sessions
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If |a| = b is a + b > ab ?
(1) a = -b
(2) a = -3
(1) a = -b
(2) a = -3
I believe its B but the MR says its D.
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maths.jpg [ 99.43 KiB | Viewed 9300 times ]
13 Jul 2010, 15:16
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yogeshagarwala
If \(|a|=b\) is \(a+b>ab\)?
First of all as \(|a|=b\) (\(b\) equals to absolute value of some number) then \(b\geq{0}\), as absolute value is always non-negative.
(1) \(a=-b\) (\(b=-a\)) --> so \(a\leq{0}\) and \(LHS=a+b=0\). But \(RHS=ab\leq{0}\) thus we can not say for sure that \(a+b>ab\), because if \(a=b=0\) then \(a+b=0=ab\) (so in case \(a=b=0\), \(a+b\) is not more than \(ab\) it equals to \(ab\)). Not sufficient.
(2) \(a=-3\) --> \(b=3\) --> \(a+b=0>ab=-9\). Sufficient.
Answer: B.
Hope it's clear.
General Discussion
whiplash2411
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13 Jul 2010, 15:10
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Given: \(|a| = b\)
To find: \(Is a+b>ab\)
Statement 1: \(a = -b\) - Sufficient
\(=> a+b = 0\)
\(ab = (-b)(b) = -b^2 < 0\)
\(0 > ab\) since ab is negative.
Statement 2: \(a = -3\) - Sufficient
\(b = |-3| = 3\)
\(=> a+b = 0\)
\(ab = (-3)(3) = -9 < 0\)
\(0 > ab\) since ab is negative.
So the answer is D.
To find: \(Is a+b>ab\)
Statement 1: \(a = -b\) - Sufficient
\(=> a+b = 0\)
\(ab = (-b)(b) = -b^2 < 0\)
\(0 > ab\) since ab is negative.
Statement 2: \(a = -3\) - Sufficient
\(b = |-3| = 3\)
\(=> a+b = 0\)
\(ab = (-3)(3) = -9 < 0\)
\(0 > ab\) since ab is negative.
So the answer is D.
