AmarSharma
If a, b, c and are positive and a^2+c^2 =202, what is the value of b-a-c?
(1) b^2+c^2=225
(2) a^2+b^2=265
from 1 we get b^2-a^2=23.
(b+a)(b-a) =23, as 23 a prime number, b+a =23 and b-a = 1, => b=12 and a =11. so c=9
Hence statement 1 is sufficient to answer the question.
Is the solution incorrect? if yes why? Help Please.
The problem with your solution is that you assume, with no ground for it, that variables represent integers only. From (b+a)(b-a)=23 you cannot say that b+a=23 and b-a=1, because for example b+a can be 46 and b-a can be 1/2.
If a, b, c and are positive and a^2+c^2=202, what is the value of b-a-c?(1) b^2+c^2=225. Not sufficient on its own.
(2) a^2+b^2=265. Not sufficient on its own.
(1)+(2) Subtract a^2+c^2=202 from b^2+c^2=225: b^2-a^2=23. Now, sum this with a^2+b^2=265: 2b^2=288 --> b^2=144 --> b=12 (since given that b is a positive number). Since b=12 then from b^2-a^2=23 we get that a=11 and from a^2+c^2=202 we get that c=9. Sufficient.
Answer: C.
Hope it's clear.
Bunuel - I have a question - The question states that a,b,c are positive. It doesn't state that they are positive integers. Essentially, I could have a=10.99 etc... Do you think that the answer would be E) then?