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19 May 2013, 09:07
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Could Experts please explain how does the explanation allow for repetitions?
I mean e.g.:
gagag = gagag
We have 3! repetitions for consonants and 2! repetisions for vowels, which made me divide 108/12=9. Yet, A is incorrect.
Source: Manhattan Test from GMAT Club Tests.
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21 May 2013, 17:53
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HumptyDumpty
Dear HumptyDumpty,
I'm happy to help with this.
As usual, MGMAT has done a brilliant job of setting up the question. They state:
The Simplastic language has only 2 unique values and 3 unique consonants.
OK, that makes clear the nature of this "alphabet", the letters available for possible words.
Then:
Every noun in Simplastic has the structure CVCVC, where C stands for a consonant and V stands for a vowel. How many different nouns are possible in Simplastic?
Where in that text, describing the nature of a "noun", does it hint at all that repeats are not allowed. When I first read the question, I scanned it, and then went back to read carefully. Very tricky. The word "unique" appears twice in the description of the alphabet, in the description of the letters available, but no such restriction appears in the description of what constitutes a "noun." Since there is no restriction, repetitions are allowed. Whatever the first consonant is, the third letter (the second consonant) could be any of the three, regardless of whether it's a repetition.
Does all this make sense?
Mike
22 May 2013, 02:32
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Whoaa! Soo mean of them to pull my leg in this way! :] On the other hand, however, I am happy that it was an overlooking and not a mathematical error. No difference on the GMAT, I know . Thank you, Mike!
. Thank you, Mike! 
. Thank you, Mike!
