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28 Jan 2009, 06:47
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In GMAT, is \(sqrt(x)\) always +ve ?
This can get really tricky in some DS questions depending on
the equations, example if we simplify equation and use x instead of
\(sqrt(x)\) and consider positive/negative numbers - could get
a wrong answer.
Any suggestions for a clean way to handle this topic is appreciated.
This can get really tricky in some DS questions depending on
the equations, example if we simplify equation and use x instead of
\(sqrt(x)\) and consider positive/negative numbers - could get
a wrong answer.
Any suggestions for a clean way to handle this topic is appreciated.
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30 Jan 2009, 14:45
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ConkergMat
There are many posts that discussed this issue in details.
Try finding some of them and go through them. They would, I believe, clear your doubt.
Refer:
7-t75259
viewtopic.php?t=39533
26 Jun 2014, 23:26
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Quoting another answer, in essence,
"In GMAT math, the roots of x are expressed as +\sqrt{x} and -\sqrt{x}
\sqrt{x} itself is ALWAYS positive. I completely understand your logic, but if you don't accept this as a convention, you are bound to either get DS sums wrong or frown on several PS sums.
For example, the solutions for x in the equation x^2 = 25 are x=5 and x=-5.
HOWEVER, if x = 25, then \sqrt{x} = 5. PERIOD. Remember, convention not logic!
Good luck!"
"In GMAT math, the roots of x are expressed as +\sqrt{x} and -\sqrt{x}
\sqrt{x} itself is ALWAYS positive. I completely understand your logic, but if you don't accept this as a convention, you are bound to either get DS sums wrong or frown on several PS sums.
For example, the solutions for x in the equation x^2 = 25 are x=5 and x=-5.
HOWEVER, if x = 25, then \sqrt{x} = 5. PERIOD. Remember, convention not logic!
Good luck!"
Archived Topic
Hi there,
Archived GMAT Club Tests question - no more replies possible.
Where to now? Try our up-to-date Free Adaptive GMAT Club Tests
for the latest questions.
Still interested? Check out the "Best Topics" block above for better discussion and related questions.
Thank you for understanding, and happy exploring!
