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27 Oct 2009, 00:33
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If \(q\) is a positive integer, is \(p\frac{q}{\sqrt{q}}\) an integer?
1. \(q = p^2\)
2. \(p\) is a positive integer
The Explanation is given as follow:
Statement (1) by itself is sufficient. We know that \(p = \sqrt{q}\) . Thus \(\sqrt{q}\frac{q}{\sqrt{q}} = q\) . Since \(q\) is a positive integer, we have enough information to answer the question.
Statement (2) by itself is insufficient. If \(p\) is a positive integer, then \(p\sqrt{q}\) may or may not be an integer, depending on \(q\) .
The correct answer is A.
Now my question is, how can we say from \(q = p^2\) that \(p = \sqrt{q}\)?
Say if P=-2 and q=4 (thus \(q = p^2\)). However, -2# \(\sqrt{4}\). So we need to know whether p is positive or negative. So the answer should be C.
Am I making any mistake? Please help.
1. \(q = p^2\)
2. \(p\) is a positive integer
The Explanation is given as follow:
Statement (1) by itself is sufficient. We know that \(p = \sqrt{q}\) . Thus \(\sqrt{q}\frac{q}{\sqrt{q}} = q\) . Since \(q\) is a positive integer, we have enough information to answer the question.
Statement (2) by itself is insufficient. If \(p\) is a positive integer, then \(p\sqrt{q}\) may or may not be an integer, depending on \(q\) .
The correct answer is A.
Now my question is, how can we say from \(q = p^2\) that \(p = \sqrt{q}\)?
Say if P=-2 and q=4 (thus \(q = p^2\)). However, -2# \(\sqrt{4}\). So we need to know whether p is positive or negative. So the answer should be C.
Am I making any mistake? Please help.
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27 Oct 2009, 02:31
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The explanation seems correct if you notice the question asks whether the term is an integer (NOT necessarily a positive integer), hence the explanation seems correct. the only issues is that the step last value should be +/- q and not just q, which is still an integer.
Hope this helps...
Hope this helps...
27 Oct 2009, 02:46
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mehulsingh
Ohh..thanks very much. I was such a careless $%$&^%!!!
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Hi there,
Archived GMAT Club Tests question - no more replies possible.
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