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15 Nov 2009, 10:30
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I think this is an error. If we plug in x < 1 and x >1 we get to different results if y =1. Stem does not state M is an interger. Am I off?
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16 Nov 2009, 01:12
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I'm sorry, I don't follow how you arrived to this conclusion. Where did you plug the values of \(X\) in?
If we take S1, we get this:
\(\sqrt{X} \gt \sqrt{Y}\)
or
\(X \gt Y\)
after we square both sides. Why would you plug in \(X \lt 1\) and \(Y =1\) in there if it says that \(X \gt Y\)? S1 is sufficient to answer the question.
Let's see what we have with S2:
\(X^2 \gt Y^2\)
I see no reason to plug \(X \lt 1\) and \(Y=1\) in here... S2 is not sufficient since plugging in X=4, Y=2 and X=-4, Y=2 produce different results while not violating S2.
I hope this helps.
If we take S1, we get this:
\(\sqrt{X} \gt \sqrt{Y}\)
or
\(X \gt Y\)
after we square both sides. Why would you plug in \(X \lt 1\) and \(Y =1\) in there if it says that \(X \gt Y\)? S1 is sufficient to answer the question.
Let's see what we have with S2:
\(X^2 \gt Y^2\)
I see no reason to plug \(X \lt 1\) and \(Y=1\) in here... S2 is not sufficient since plugging in X=4, Y=2 and X=-4, Y=2 produce different results while not violating S2.
I hope this helps.
ajonas
Archived Topic
Hi there,
Archived GMAT Club Tests question - no more replies possible.
Where to now? Try our up-to-date Free Adaptive GMAT Club Tests
for the latest questions.
Still interested? Check out the "Best Topics" block above for better discussion and related questions.
Thank you for understanding, and happy exploring!
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