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Suppose you take the case of rolling two die and trying to calculate the probability of getting a total more than 10.
So out of 36 possible outcomes you get :-
A B
5,6
6,5
6,6
6,6*
The last one is what confuses me - most sources don't consider it but I feel the prob should be 4/36 rather than 3/36. If you ignore the possibility of the either of the dice turning up sixes as two separate events aren't you messing with the identity of the dice ?
I may be way off track and I don't mean to shake the very foundations of probability what do you say ?
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Suppose you take the case of rolling two die and trying to calculate the probability of getting a total more than 10.
So out of 36 possible outcomes you get :-
A B 5,6 6,5 6,6 6,6*
The last one is what confuses me - most sources don't consider it but I feel the prob should be 4/36 rather than 3/36. If you ignore the possibility of the either of the dice turning up sixes as two separate events aren't you messing with the identity of the dice ?
I may be way off track and I don't mean to shake the very foundations of probability what do you say ?
Show more
Are you trying to say that the probability of rolling 6-6 is 2/36??? The probability of the sum being >10 is the probability the sum is 11 + the probability the sum is 12. There are 2 ways the sum can be 11: die A = 6, die B = 5 OR die A = 5, die B = 6. There is only 1 way the sum can be 12: die A = 6, die B = 6. Since there are no differentiating characteristics between the 6s, this is the only way you can roll a 12.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.