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BN1989
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BN1989
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Let's say you had two intersecting sets...A and B; and you would like to calculate A union B.

How would you do it?
..... A + B - (A intersection B). Right?

Now, ask yourself why did you subtract (A intersection B) just once?
... because when you added A and B, the common element (A intersection B) got counted twice. You needed it just once, so you subtracted it once.

Applying the same logic, to three sets:
When you calculate [A union B union C] by adding A + B + C, the (A intersection B intersection C) piece gets counted three times. You need it accounted for just once, so you subtract it twice.

Makes sense?

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