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pb_india
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Ques=> 1.5 kg A and 6 kg B is mixed together, then bagged 11 Jan 2005, 13:34
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1.5 kg A and 6 kg B is mixed together, then bagged in 0.25 kg per bag. The price of such mixture is $1.5/bag. If A and B are sold separately, the total sales value of A is equal to that of B. If the sales value of mixture is 50 percent more than the total sales value of A and B, what is the price of A?


A. $5
B. $7
C. $10
D. $18
E. $20



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Ques=> 1.5 kg A and 6 kg B is mixed together, then bagged 11 Jan 2005, 13:49
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Price of A = 10$

let me know if this is correct i will post my explnation
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pb_india
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Ques=> 1.5 kg A and 6 kg B is mixed together, then bagged 11 Jan 2005, 13:50
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Yes OA. is $10
Please post explanation
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rxs0005
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Ques=> 1.5 kg A and 6 kg B is mixed together, then bagged 11 Jan 2005, 14:07
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Total price of mixture 7.5 total bags = 7.5 / .25 = 30 bags

Total price = 30 * 1.5 = 45

Individalu price 45 /1.5 = 30$

let now A/ B price of mixture

Given 1.5A = 6B ----I

And we know now

1.5A + 6B = 30$ --------- II

from I / II

A = 10$
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Ques=> 1.5 kg A and 6 kg B is mixed together, then bagged 11 Jan 2005, 14:32
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Hey rx0005 what is the "individual price of $30? I don't understand...

I get the part about adding the weights:

1.5 kg A + 6.0 kg B = 7.5 kg AB mix


7.5 kg/0.25 kg/bag = 30 bags


30 bags * $1.5/bag = $45

From there I get a little confused, how did you get $30, what is that number?

A = B but when mixture A + B * 1.5 = A or B right, isn't taht what the question says...I would appreciate it if you could explain your answer a little more...thanks.
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Ques=> 1.5 kg A and 6 kg B is mixed together, then bagged 11 Jan 2005, 17:04
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Sorry doode got caught in traffic here !

The solution is simple

Now after mixing the bag we get 30 bags from 7.5 kilos total so he sells them for 1.5$ a bag
so total sale from A and B mixture = 30 * 1.5 = 45$

the problems states

"If the sales value of mixture is 50 percent more than the total sales value of A and B"

So the mixture (45$) is 50% more than the value of A and B individual total

that is you can say the cost price of A and B
so le tht be x so x*150% = 45 or 45 /1.5 = 30$

so A and B cost 30$ then the rest is just solving the 2 eq

hope u get it if not i will try to explain again.
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Ques=> 1.5 kg A and 6 kg B is mixed together, then bagged 12 Jan 2005, 08:24
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I think the question stem has to say the price of A per KG. Otherwise, it is slighly confusing.

rxs0005
Sorry doode got caught in traffic here !

The solution is simple

Now after mixing the bag we get 30 bags from 7.5 kilos total so he sells them for 1.5$ a bag
so total sale from A and B mixture = 30 * 1.5 = 45$

the problems states

"If the sales value of mixture is 50 percent more than the total sales value of A and B"

So the mixture (45$) is 50% more than the value of A and B individual total

that is you can say the cost price of A and B
so le tht be x so x*150% = 45 or 45 /1.5 = 30$

so A and B cost 30$ then the rest is just solving the 2 eq

hope u get it if not i will try to explain again.
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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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