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ywilfred
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Antmavel
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ywilfred
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banerjeea_98
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"D"

hmmm.....let's take 101 as the prime number....we know that all total days = 30

days multiple of 5s = 5,10,15,20,25,30......if which 15,30 will not yield finite decimals as it contains a 3....so now we have 4 possible days.

days multiple of 2s, but not any other prime number = 2,4,8,16 = 4 days

Also day 1 will always yield to whole number


total number of favorable days = 9

p(e) = 9/30 = 3/10
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both of you are right, and banerjeea_98 is spot on with his explanation.
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banerjeea_98
"D"

hmmm.....let's take 101 as the prime number....we know that all total days = 30

days multiple of 5s = 5,10,15,20,25,30......if which 15,30 will not yield finite decimals as it contains a 3....so now we have 4 possible days.

days multiple of 2s, but not any other prime number = 2,4,8,16 = 4 days

Also day 1 will always yield to whole number


total number of favorable days = 9

p(e) = 9/30 = 3/10


terrific ! :cool
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banerjeea_98
"D"

hmmm.....let's take 101 as the prime number....we know that all total days = 30

days multiple of 5s = 5,10,15,20,25,30......if which 15,30 will not yield finite decimals as it contains a 3....so now we have 4 possible days.

days multiple of 2s, but not any other prime number = 2,4,8,16 = 4 days

Also day 1 will always yield to whole number


total number of favorable days = 9

p(e) = 9/30 = 3/10

Hi Banerjeera, could you please explain your reasoning here. Thanks



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