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Hi, Does the above statement is meant to convey that the quotient is even ? or is it meant to convey that the remainder is 0? I am particularly concerned with the word "evenly". Thanks, in advance!
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Hi, Does the above statement is meant to convey that the quotient is even ? or is it meant to convey that the remainder is 0? I am particularly concerned with the word "evenly". Thanks, in advance!
Hi, Does the above statement is meant to convey that the quotient is even ? or is it meant to convey that the remainder is 0? I am particularly concerned with the word "evenly". Thanks, in advance!
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I think the other way. Evenly means that when we divide 12 by 3 we have an even quotient as 4 and remainder as zero. For 15, I will say 3 goes into 15 oddly.
Hi, Does the above statement is meant to convey that the quotient is even ? or is it meant to convey that the remainder is 0? I am particularly concerned with the word "evenly". Thanks, in advance!
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The above statement just means that 12 is divisible by 3,ergo zero remainder. It has got nothing to do with the quotient being even/odd.
Ex- 3 goes evenly into 15.
It just means that 15 can be divided into 5 equal(even) parts.
Hi, Does the above statement is meant to convey that the quotient is even ? or is it meant to convey that the remainder is 0? I am particularly concerned with the word "evenly". Thanks, in advance!
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x divides k evenly, just means that x is a factor of k, divides k without leaving a remainder. For example, 3 divides 12 evenly --> 12/3=4.
Hi, Does the above statement is meant to convey that the quotient is even ? or is it meant to convey that the remainder is 0? I am particularly concerned with the word "evenly". Thanks, in advance!
Show more
"Evenly" has remainder of 0, and 12 can be evenly distributed into 3 groups. What consists of those groups (4) shouldn't derive if a number is "gone into" evenly or oddly. Basically, I'm not so sure on what was said about "oddly"; I've never seen that before.
I hope this helps.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.