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sudhagar
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chets
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HIMALAYA
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gsr
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There has to be a pattern here. Let's see -
7^1 = 7 (rem - 2 when div by 5)
7^2 = 49 (rem - 4)
7^3 = 343 (rem - 3)
7^4 = 2401 (rem - 1)
7^5 = 16807 (rem - 2)
7^6 = 117649 (rem - 4)
...
I would stop here and believe that there is a pattern in the remainder, else I'll be doing this problem for whole duration of the test (and may still not complete it in the end! :) )

7^381 = 7^(4(95) + 1)
so this is the 5 th in the sequence pattern and hence has the remainder as 2
Am I correct! Please say yes! :lol:
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sudhagar
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gsr your answer is correct. But Chets approach is more preferred. Reason, it involves less calculation; hence less prone to error and saves time.

Hope you agree with me.
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gsr
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sudhagar, It's true. I agree. But both methods are same and to make it more explainatory (one won't this liberty in the exam!), i listed out all the digits :)



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