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A teacher assigns students to rooms in such a way that some of the rooms can be empty and more than one student can be assigned to a room. In how many ways can the teacher assign 3 students to 2 different rooms?
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Edit: First, i thought there 3 different romms instead of 2.
C (3:2)=3 (ways to choose 2 students out of 3)
AB/C, AC/B, BC/A
However, the order of rooms matter and there 2 ways to assign 2 students together and 1 student in 2 separate rooms
R#1 R#2
AB/ C
C/ AB
2³=8, each student can be assigned to two rooms, without restrictions.
I also got 8.
Hey allabout. How did you get this 2³ I mean 2 raise to 3.
Bhai,
I think the explanation goes like this: For each student there are 2 choices: Room 1 or Room 2
Hence Total choices = 2 * 2 * 2 = 8.
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I meant hos did he get 3 over 2. we write 2^3. See how allabout did 3 little above 2. I think you can do it only if you copy from somewhere it was already formatted.
2³=8, each student can be assigned to two rooms, without restrictions.
I also got 8.
Hey allabout. How did you get this 2³ I mean 2 raise to 3.
Bhai,
I think the explanation goes like this: For each student there are 2 choices: Room 1 or Room 2
Hence Total choices = 2 * 2 * 2 = 8.
I meant hos did he get 3 over 2. we write 2^3. See how allabout did 3 little above 2. I think you can do it only if you copy from somewhere it was already formatted.[/quote]
Hmm. That part I don't know I am not good at formatting stuff anyways...
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Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.