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joemama142000
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Each of a group of children has 3 blue markers and 1 red 31 Jan 2006, 14:55
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Each of a group of children has 3 blue markers and 1 red marker or 2 red markers and 1 blue marker. If the average number of red markers that each child has is 1.6, what is the average number of blue markers that each child has?



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Each of a group of children has 3 blue markers and 1 red 31 Jan 2006, 15:38
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1.8

let there be:
m children with 3B 1R
n children with 1B 2R

given:
(m + 2n) / (m+n) = 1.6 OR
m:n = 2:3

let:
m = 2x
n = 3x

avg blue markers = (3 * 2x + 1 * 3x) / (2x + 3x) = 9x/5x = 1.8
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lhotseface
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Each of a group of children has 3 blue markers and 1 red 31 Jan 2006, 15:49
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1.8 Same working as duttsit.
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joemama142000
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Each of a group of children has 3 blue markers and 1 red 31 Jan 2006, 18:52
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how do you get the bolded part?

duttsit
1.8

let there be:
m children with 3B 1R
n children with 1B 2R

given:
(m + 2n) / (m+n) = 1.6 OR
m:n = 2:3

let:
m = 2x
n = 3x

avg blue markers = (3 * 2x + 1 * 3x) / (2x + 3x) = 9x/5x = 1.8
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Each of a group of children has 3 blue markers and 1 red 31 Jan 2006, 18:53
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Total # of children = n
Total # of children with 3 blue markers + 1 red marker = p
Total # of children with 1 blue marker + 2 red marker = n-p

Total # of red markers = p*1 + (n-p)*2 = 2n-p
Average # of red markers per child = (2n-p)/n = 1.6 -> 2n-p=1.6n -> 0.4n = p

Total # of blue markers = 3p + (n-p) = 2p+n
Average # of blue markers = (2p+n)/n = (0.8n+n)/n = 1.8
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Each of a group of children has 3 blue markers and 1 red 01 Feb 2006, 10:30
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joemama142000
how do you get the bolded part?

duttsit
1.8

let there be:
m children with 3B 1R
n children with 1B 2R

given:
(m + 2n) / (m+n) = 1.6 OR
m:n = 2:3

let:
m = 2x
n = 3x

avg blue markers = (3 * 2x + 1 * 3x) / (2x + 3x) = 9x/5x = 1.8
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The bolded part are "total" number of markers with children.
For instance, the first one is the total number of red markers with children.
m children has 1 marker each
n children has 2 markers each

so total markers: 1*m + 2*n = m + 2n
To find avg number of markers for each child just divide this total with number of children (m+n).
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Each of a group of children has 3 blue markers and 1 red 01 Feb 2006, 17:55
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oa is 1.8

thanks for your help guys
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mxr55820
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Each of a group of children has 3 blue markers and 1 red 02 Feb 2006, 14:09
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just wanted to show another way of doing it:

total Red marker:
let X children have 1 and Y children have 2
1X + 2Y = 1.6 (X+Y) = must be whole number as total cannot be fraction
= 1.6 (5) = 8 (assuming x+y = 5)
so,
X = 2
Y = 3
total blue marker:
(children either have 1 RM and 3BM or 2 RM and 1 BM)
3X + 1Y = 3*2 + 1*3 = 9
average 9/5 = 1.8



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
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