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joemama142000
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The population of a certain bacteria is donated by X. In 20 20 Feb 2006, 23:39
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The population of a certain bacteria is donated by X. In 20 years, the populatioin will increase by 4% every two years. 20 years later, the population will increase by 2% every 4 years. What is the population in the end of the 32nd year?



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bewakoof
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The population of a certain bacteria is donated by X. In 20 20 Feb 2006, 23:54
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Should be x( 1.04^10 + 1.02^3)
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petefroml
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The population of a certain bacteria is donated by X. In 20 21 Feb 2006, 01:13
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x*(1.04)^10*(1.02)^3
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razrulz
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The population of a certain bacteria is donated by X. In 20 21 Feb 2006, 04:36
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started off.. thot it will be a long way

but the answers posted by others made me stop.. same conclusion

x { (1.04)^10 + (1.02)^3) }
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joemama142000
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The population of a certain bacteria is donated by X. In 20 21 Feb 2006, 17:44
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can you guys explain in detail? I know this is the compound interest formula but im not sure how to apply it. thanks
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ps_dahiya
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The population of a certain bacteria is donated by X. In 20 21 Feb 2006, 19:42
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Amount = P * (1+ r/100)^y where

P is the principal amount
r is the interest rate per unit
and y is the total duration in the units above.

For example if the interest rate is 10% per annum and compounded half yearly, 200 is the principal amout and we have to find amount after 2 years then

Amount = 200 * (1+5/100)^4
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willget800
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The population of a certain bacteria is donated by X. In 20 21 Feb 2006, 21:02
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I think it is compound interest right.. It increases every 2 years..

This is what i got..

X*[(1.02)^20]*[(1.005^12)]

If my answer is right.. i will try to explain..
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tomgw
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The population of a certain bacteria is donated by X. In 20 22 Feb 2006, 15:09
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also for x*[(1,04)^10 + (1.02)^3]
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joemama142000
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The population of a certain bacteria is donated by X. In 20 22 Feb 2006, 20:57
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the oa i have is x*(1.04)^10*(1.02)^3



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