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A.

St1: If (x +6)/3 remainder is 1 then x/3 remainder will also be 1. SUFF

St2: If x = SQRT(7) then (x^2)/3 remainder is 1 and x/3 remainder is @%^(*^^$@$@%

If x = 4 then (x^2)/3 remainder is 1 and x/3 remainder is 1. INSUFF
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ps_dahiya,

What if x+6 = -2 + 6 = 4 for statement I ?


ps_dahiya
A.

St1: If (x +6)/3 remainder is 1 then x/3 remainder will also be 1. SUFF

St2: If x = SQRT(7) then (x^2)/3 remainder is 1 and x/3 remainder is @%^(*^^$@$@%

If x = 4 then (x^2)/3 remainder is 1 and x/3 remainder is 1. INSUFF
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lhotesface,
even if x is negative, statement (A) is sufficient.
Remainder is always considered to be positive. So, in your example, if if x = -2, remainder will be 1 which is same as (x+4) % 6. (% is for remainder here).
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Here is what I was thinking...pls point out the flaw ?

Statement II:

Let x = -2 => x+6 when divided by 3 leaves a remainder of 1.
So in the main question stem when -2 is divided by 3, the remainder is 2...right ?

Let x = 4 => x+6 when divided by 3 leaves a remainder of 1.
So in the main question stem when 4 is divided by 3, the remainder is 1.





chuckle
lhotesface,
even if x is negative, statement (A) is sufficient.
Remainder is always considered to be positive. So, in your example, if if x = -2, remainder will be 1 which is same as (x+4) % 6. (% is for remainder here).
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lhotseface
ps_dahiya,

What if x+6 = -2 + 6 = 4 for statement I ?


ps_dahiya
A.

St1: If (x +6)/3 remainder is 1 then x/3 remainder will also be 1. SUFF

St2: If x = SQRT(7) then (x^2)/3 remainder is 1 and x/3 remainder is @%^(*^^$@$@%

If x = 4 then (x^2)/3 remainder is 1 and x/3 remainder is 1. INSUFF


If I am correct I have read at many places that remainder can not be -ve. Only the quotient can be -ve.

Lets take your case lhotseface.
What if x+6 = -2 + 6 = 4 for statement I ?

Then x/3 is -2/3 which can be represented as -1 + 1/3 and quotient is -1 and remainder is 1.

Hope this helps. I don't remember other links, but one of the many links I read is below:

https://mathforum.org/library/drmath/view/52343.html
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I GET A BUT can anyone show how to handle statement 2 ?

Where does this question come from ?

OA plz
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Professor
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lhotseface
Here is what I was thinking...pls point out the flaw ?

Statement II:

Let x = -2 => x+6 when divided by 3 leaves a remainder of 1.
So in the main question stem when -2 is divided by 3, the remainder is 2...right ?

Let x = 4 => x+6 when divided by 3 leaves a remainder of 1.
So in the main question stem when 4 is divided by 3, the remainder is 1.

chuckle
lhotesface,
even if x is negative, statement (A) is sufficient.
Remainder is always considered to be positive. So, in your example, if if x = -2, remainder will be 1 which is same as (x+4) % 6. (% is for remainder here).


E make sense.

imo, the question is poorly designed one. guys, donot worry about questions like this one because these kind of questions are less likely to be appeared in gmat.



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