This is a simple question on the concept of Average Speed. Observe that the question mentions that Angela returns along the same route on her return journey. This is to tell you that the distance that she covered in both the cases is same.
When the same distance is covered at a kmph and b kmph respectively,
Average Speed = \(\frac{2ab}{a+b}\).
Also remember that, Average Speed = \(\frac{Total Distance travelled}{Total time taken}\).
Let the length of the trail be ‘d’ kilometres. From the question, we know that the total time taken is 105 minutes.
Do not forget to convert the time above to hours, since the speed values have been given in terms of km per hour. Forgetting to convert 105 minutes to hours could mean a wrong answer, albeit not in this question, since the options are not framed so as to reflect a mistake like that.
105 minutes = \(\frac{105}{60}\) = 1 ¾ hours = \(\frac{7}{4}\) hours.
In this case, speed of Angela’s onward journey = a = 3 kmph and speed of Angela’s return journey = b = 4 kmph.
Substituting all the above values in the equations,
\(\frac{2 * 3 * 4}{3 + 4}\) = \(\frac{2d}{(7/4)}\), which on simplification gives us 2d = 6 km or d = 3 km
The correct answer option is D.
There are two areas in Quant where you need to be super aware of taking care of the conversions between units – Mensuration and Speed, Time & Distance. Always pay attention to the units mentioned in the question and the units given in the answers, so that you know whether you have to convert or not.
Hope this helps!