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Andre_p
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Andre_p
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Well since 3 candidates are out, leaves 25 students to vote. Since each of these 25 can vote for either of the 3 candidates, to have a majority the winning candidate should get more than 25 / 3 votes.

But 25 / 3 = 8.33... and since people can only be integers, anybody who gets 9 votes will be a winner.

so the percentage would be 9/25 * 100 = 36%.

HTH...
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Andre_p
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Perfect!! Makes total sense. Thanks. I'm extremely mathematically challenged...
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trivikram
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vipin7um
Well since 3 candidates are out, leaves 25 students to vote. Since each of these 25 can vote for either of the 3 candidates, to have a majority the winning candidate should get more than 25 / 3 votes.

But 25 / 3 = 8.33... and since people can only be integers, anybody who gets 9 votes will be a winner.

so the percentage would be 9/25 * 100 = 36%.

HTH...


Neat way of solving this type of problem
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Andre_p
In a class of 28 students, one student is to be elected as class rep. Three of the 28 students are running for the position. The three candidates may not vote, but all others must vote. What is the smallest percent of votes with which a candidate could win?

a. 25%
b. 33.34%
c. 34%
d. 36%
e. 50.1%


Is they may not vote = they cannot vote?

The three candidates may not vote - means they may vote

so smallest margin could be 10, 9, 9 = 28

therefore % = 10/28 = 0.3571 ~36%
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D.

25 voters for 3 post,if they get 8,8,9, the one who gets 9 wins. the smallest percentage of vote must be (9/25)*100 =36%


Andre_p
In a class of 28 students, one student is to be elected as class rep. Three of the 28 students are running for the position. The three candidates may not vote, but all others must vote. What is the smallest percent of votes with which a candidate could win?

a. 25%
b. 33.34%
c. 34%
d. 36%
e. 50.1%



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