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willget800
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ywilfred
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willget800
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i like your second way of doing things?
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Charlie45
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Quote:
I just wanted to add one more way of solving this.

The number of ways to arrange 5 poeple = 5! = 120 (Or 5P5) (This will always be the same, no matter what method you use)

Then let's consider a and b as 1 entity, so now we need to arrage (ab),c,d,e and the number of ways to do this is 4! = 24. Again, we need to consider reverse order, ba. So total = 48 ways.

Probability = 1-48/120 = 3/5

The difference in this method is that instead of writing down possible seating arrangements, we can just lump a and b together to be considered as 1 entity. It's faster and less error-prone.


Very helpful, Ywilfred. Thanks.



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