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getzgetzu
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E for me too.

1) xy = even, hence x can be odd or even. We don't know what z is hence cannot say whther xz is even or odd.

2)yz is even. Again no idea about x

Both;
xy =even and yz is even But anynumber can be even or odd. so cannot conclusively say if xz is even or odd
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The answer is E.

if y is even then xy and yz will always be even.

So it doesn't provide any information about x and z.



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