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consultinghokie
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2)(3)(4)(7)(11)(13) ) / ( (21)(y) ) what are possible values 09 May 2006, 14:31
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( (2)(3)(4)(7)(11)(13) ) / ( (21)(y) )

what are possible values of y?

my approach was to factor 21 ---> 7, 3 and cancel those out. Then I'm left with 2, 4, 7, 11, 13.

what is the next step?



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2)(3)(4)(7)(11)(13) ) / ( (21)(y) ) what are possible values 09 May 2006, 14:56
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The next step is to find out all possible products of these numbers when
each of the factors can be either with a power of 1 or 0.
If the question allows a negative integer as a result, do not forget
to add all of them with a negative sign.
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2)(3)(4)(7)(11)(13) ) / ( (21)(y) ) what are possible values 09 May 2006, 18:12
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consultinghokie
( (2)(3)(4)(7)(11)(13) ) / ( (21)(y) )

what are possible values of y?

my approach was to factor 21 ---> 7, 3 and cancel those out. Then I'm left with 2, 4, 7, 11, 13.

what is the next step?
Show more


your question is not clear and complete. if you are looking for the value of y given that ((2)(3)(4)(7)(11)(13)) / ((21)(y)) is a positive integer, y could have 31 different values as under:

= 5 + 5c2 + 5c3 + 5c4 +5c5 = 31.
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2)(3)(4)(7)(11)(13) ) / ( (21)(y) ) what are possible values 09 May 2006, 19:44
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Agreed. If the end is an integer, then y would be a combination of any of the factors 2,2,3,11,13
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2)(3)(4)(7)(11)(13) ) / ( (21)(y) ) what are possible values 09 May 2006, 19:48
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consultinghokie
( (2)(3)(4)(7)(11)(13) ) / ( (21)(y) )

what are possible values of y?

my approach was to factor 21 ---> 7, 3 and cancel those out. Then I'm left with 2, 4, 7, 11, 13.

what is the next step?

your question is not clear and complete. if you are looking for the value of y given that ((2)(3)(4)(7)(11)(13)) / ((21)(y)) is a positive integer, y could have 31 different values as under:

= 5 + 5c2 + 5c3 + 5c4 +5c5 = 31.
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hmmmmmmm..................

i guess i should consider 4 as 2x2.
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2)(3)(4)(7)(11)(13) ) / ( (21)(y) ) what are possible values 10 May 2006, 10:54
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ah, so with this type of problem, you would just look at the answer choices and find the one that's a factor of the remaining numbers in the numerator. got it.
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2)(3)(4)(7)(11)(13) ) / ( (21)(y) ) what are possible values Updated on: 11 May 2006, 02:43
Originally posted by Dilshod on 11 May 2006, 00:20.
Last edited by Dilshod on 11 May 2006, 02:43, edited 1 time in total.
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Hi,
the question is not clear, since we don’t know whether y is an integer, decimal or fraction.
If we assume that y is positive integer, then there are there are 15 possible values for y
2* 4* 11* 13/y

sorry, forgot 1. So there are 16 possible values for y
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2)(3)(4)(7)(11)(13) ) / ( (21)(y) ) what are possible values 11 May 2006, 00:45
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consultinghokie
( (2)(3)(4)(7)(11)(13) ) / ( (21)(y) )

what are possible values of y?

my approach was to factor 21 ---> 7, 3 and cancel those out. Then I'm left with 2, 4, 7, 11, 13.

what is the next step?

your question is not clear and complete. if you are looking for the value of y given that ((2)(3)(4)(7)(11)(13)) / ((21)(y)) is a positive integer, y could have 31 different values as under:

= 5 + 5c2 + 5c3 + 5c4 +5c5 = 31.

hmmmmmmm..................

i guess i should consider 4 as 2x2.
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This is a good approach but I think its wrong as it does consider 2*2*13 and 2*13*2 as two differnt numbers

What we are looking for is different factors of 2^3*11*13

We can say represent each factor as 2^x * 11^y * 13^z

x can be 0,1,2,3
y can be 0, 1
z can be 0,1

so we will have 4*2*2 = 16 different factors.



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!