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07 Jun 2006, 01:12
Kudos
Bookmarks
Easy one for u
x,y are non-zero intergers. what is the remainder when x is divided by y
(1) x/2y remainder is 4
(2) (x+y)/y remainder is 4
x,y are non-zero intergers. what is the remainder when x is divided by y
(1) x/2y remainder is 4
(2) (x+y)/y remainder is 4
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07 Jun 2006, 02:43
Kudos
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I think it's D.
(1) x/2y remainder is 4
In this case the remainder when x is divided by y is always the "remainder when 4 is divided by y".
For ex : -
Suppose x = 34, y = 5, So x/2y or 34/10, remainder is 4.
when we divide 4 by y (5 in this case), remainder is 4.
In actual x/y in our case is 34/5; remainder 4.
Another example, suppose x = 22 and y= 3, So x/2y or 22/6, remainder is 4.
when we divide 4 by y (3 in this case), remainder is 1.
In actual x/y in our case is 22/3; remainder 1.
So equation 1 is sufficient.
(2) (x+y)/y remainder is 4
In this case the remainder is always 4.
It is also sufficient.
(1) x/2y remainder is 4
In this case the remainder when x is divided by y is always the "remainder when 4 is divided by y".
For ex : -
Suppose x = 34, y = 5, So x/2y or 34/10, remainder is 4.
when we divide 4 by y (5 in this case), remainder is 4.
In actual x/y in our case is 34/5; remainder 4.
Another example, suppose x = 22 and y= 3, So x/2y or 22/6, remainder is 4.
when we divide 4 by y (3 in this case), remainder is 1.
In actual x/y in our case is 22/3; remainder 1.
So equation 1 is sufficient.
(2) (x+y)/y remainder is 4
In this case the remainder is always 4.
It is also sufficient.
07 Jun 2006, 03:33
Kudos
Bookmarks
Sorry, am not sure I understand the logic at all.
For statement (1), leaving aside if x/2y is the same as 4/y - you have taken two examples where x/2y has remained 4, but x/y has had different remainders. Clearly, for different values of x&y, the reminder for x/y is different. Statement (1) therefore is insufficient.
For statement (1), leaving aside if x/2y is the same as 4/y - you have taken two examples where x/2y has remained 4, but x/y has had different remainders. Clearly, for different values of x&y, the reminder for x/y is different. Statement (1) therefore is insufficient.
You found the trick here
