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03 Jul 2006, 19:34
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Just for practice..
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
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03 Jul 2006, 20:49
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26. D
st. 1
if m^2=integer, this means m=integer. Suff.
st. 2
if sqrt(m)=integer, means that m=perfect square. Though +ve and -ve.
Suff.
-------------------------------------
27. C
P(not M) = 1-1/4=3/4
P(not P) = 1-2/5 = 3/5
P(not W) = 1-3/8=5/8
P(no one getting it right) = (3/4)*(3/5)*(5/8) = 9/32
therefore, at least one getting it right = 1-9/32 = 23/32
st. 1
if m^2=integer, this means m=integer. Suff.
st. 2
if sqrt(m)=integer, means that m=perfect square. Though +ve and -ve.
Suff.
-------------------------------------
27. C
P(not M) = 1-1/4=3/4
P(not P) = 1-2/5 = 3/5
P(not W) = 1-3/8=5/8
P(no one getting it right) = (3/4)*(3/5)*(5/8) = 9/32
therefore, at least one getting it right = 1-9/32 = 23/32
03 Jul 2006, 23:37
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Q26.
B
St1: Say m^2= 8 then m is not an integer and m^3 will also be a non-integer. Say m^2 = 9 then m is an integer and m^3 will be an integer.: INSUFF
St2: if SQRT(m) is an integer then m will always be an integer and m^3 will always be an integer.: SUFF
Q27.
C
Prob of all getting wrong = 3/4 * 3/5 * 5/8 = 9/32
Prob of atleast one of them getting right = 1-9/32 = 23/32
B
St1: Say m^2= 8 then m is not an integer and m^3 will also be a non-integer. Say m^2 = 9 then m is an integer and m^3 will be an integer.: INSUFF
St2: if SQRT(m) is an integer then m will always be an integer and m^3 will always be an integer.: SUFF
Q27.
C
Prob of all getting wrong = 3/4 * 3/5 * 5/8 = 9/32
Prob of atleast one of them getting right = 1-9/32 = 23/32
, and i suck at probability questions. 
