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apollo168
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Problem solving involving radicals 27 Aug 2006, 09:18
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Hi guys,

Try this one out.



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gk3.14
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Problem solving involving radicals 27 Aug 2006, 09:39
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[1/ sqrt(3) - sqrt(2)]^2 = 1/ 3+2 - 2sqrt(6) = 1/5-2sqrt(6)
~ 1/.2 = 5

Ans B?
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apollo168
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Problem solving involving radicals 27 Aug 2006, 09:48
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My fault careless mistake on my part.

Answer is E 5+2squareroot of 6
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gk3.14
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Problem solving involving radicals 27 Aug 2006, 09:55
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apollo168,
can you show how?
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apollo168
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Problem solving involving radicals 27 Aug 2006, 10:00
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gk3.14
[1/ sqrt(3) - sqrt(2)]^2 = 1/ 3+2 - 2sqrt(6) = 1/5-2sqrt(6)
~ 1/.2 = 5

Ans B?
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Sure

1/ sqrt(3) - sqrt(2)]^2 = 1/ 3+2 - 2sqrt(6) = 1/(5-2sqrt(6))

Multiplying the numerator and the denominator by (5+2sqrt(6)) we get

(5+2sqrt(6))/ (25-24)--> 5+2sqrt(6)
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hisharma
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Problem solving involving radicals 27 Aug 2006, 10:09
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straight E,
Just normalize the denominator ..
[(1/(sqrt(3)-sqrt(2))) * ( sqrt(3)+sqrt(2))/( sqrt(3)+sqrt(2)) ]^2.
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haas_mba07
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Problem solving involving radicals 27 Aug 2006, 10:13
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Answer: E

Normalize after squaring and you get 5+2xsqrt(6).
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Yurik79
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Problem solving involving radicals 27 Aug 2006, 10:43
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apollo168
gk3.14
[1/ sqrt(3) - sqrt(2)]^2 = 1/ 3+2 - 2sqrt(6) = 1/5-2sqrt(6)
~ 1/.2 = 5

Ans B?

Sure

1/ sqrt(3) - sqrt(2)]^2 = 1/ 3+2 - 2sqrt(6) = 1/(5-2sqrt(6))

Multiplying the numerator and the denominator by (5+2sqrt(6)) we get

(5+2sqrt(6))/ (25-24)--> 5+2sqrt(6)
Show more

same working
Agree E
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GMATT73
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Problem solving involving radicals 01 Sep 2006, 01:10
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apollo168
gk3.14
[1/ sqrt(3) - sqrt(2)]^2 = 1/ 3+2 - 2sqrt(6) = 1/5-2sqrt(6)
~ 1/.2 = 5

Ans B?

Sure

1/ sqrt(3) - sqrt(2)]^2 = 1/ 3+2 - 2sqrt(6) = 1/(5-2sqrt(6))

Multiplying the numerator and the denominator by (5+2sqrt(6)) we get

(5+2sqrt(6))/ (25-24)--> 5+2sqrt(6)
Show more


Nice One. Got (E). normalize the denominator and it cancels out.



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Thank you for understanding, and happy exploring!