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yezz
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Each digit in the two-digit number G is halved to form a new 07 Sep 2006, 03:40
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Each digit in the two-digit number G is halved to form a new two-digit number H. Which of the following could be the sum of G and H?


A 153
B 150
C 137
D 129
E 89

please explain



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Each digit in the two-digit number G is halved to form a new 07 Sep 2006, 04:11
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The sum is less than 150. So A and B are out. Start with units digit-127. from stem X+2X=7. Doesn't work so 127 is out. Go to D and E, The sum of the units is 9 which is 3+6 so now go to tens digits. 2T+T=8 , doesn't work. The only option left is 129 which is 86+43
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Each digit in the two-digit number G is halved to form a new 07 Sep 2006, 04:37
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Each digit in the two-digit number G is halved to form a new two-digit number H. Which of the following could be the sum of G and H?

doesnt this means that the original two digit number say (xy) has two even digits( so we can divide them by to to give another two digits)

THUS, the original number (xy) where x and y could only belong to the set of even numbers<10 ie (2,4,6,8)


thus the max the original number can be is 88 and the new one would be 44

88+44 = 132 thats the maximum we can get thus a,b,c are out

and we can now check the remaining two and we can reach that the answer is d

am i right ....or completely nuts :lol:
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Each digit in the two-digit number G is halved to form a new 07 Sep 2006, 06:08
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BG
The sum is less than 150. So A and B are out. Start with units digit-127. from stem X+2X=7. Doesn't work so 127 is out. Go to D and E, The sum of the units is 9 which is 3+6 so now go to tens digits. 2T+T=8 , doesn't work. The only option left is 129 which is 86+43
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My answer is (B)

The stem doesn't specify that both digits of G must be the same (this is a trap)

Let x = 10s digit, ley y=1s digit of G

x+y+x/2+y/2 ---> 3x/2 + 3y/2 ---> 3/2 (x+y)

The only answer choice than can be bothe a multiple of 3 and divisor of 2 is 150.
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Each digit in the two-digit number G is halved to form a new 07 Sep 2006, 07:20
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D

G = 86
H = 43
Sum = 129
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Each digit in the two-digit number G is halved to form a new 07 Sep 2006, 07:35
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Yezz,

Your explanation is the best. Nice way of implementing elimination process.
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Each digit in the two-digit number G is halved to form a new 07 Sep 2006, 08:19
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I did this way:

The sum must be divisible by 3. So eliminate C and E.
Both digits of the larger number should be even.

A. 153*2/3 = 102: Not possible.
B. 150*2/3 = 100: not possible
D. 129*2/3 = 86: BINGO!!!!
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Each digit in the two-digit number G is halved to form a new 07 Sep 2006, 08:42
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My way was not very efficient but here it is.

I just divided by 3 and if I got an integer I multiplied by two and just observed whether the digits fit.

So for 129 / 3 = 43
43 * 2 = 86

By observation it was correct.

I also used a strategy that I picked up from either Kaplan or Princeton and that is to start with E/D when trying that because the test makers usually put the right answer at the bottom for questions like this to use up your time.
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Each digit in the two-digit number G is halved to form a new 07 Sep 2006, 08:56
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D 129

G = 10x + y
H = 10x/2 + y/2 = (10x +y)/2
= G/2
G+H = 3G/2

Therefore, sum should be divisible by 3, and 2 digit.

Only D survives.

Answer: D
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Each digit in the two-digit number G is halved to form a new 07 Sep 2006, 10:48
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jainvik7 Thanks for the complement
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Each digit in the two-digit number G is halved to form a new 07 Sep 2006, 10:49
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Zagros

forget about this strategy

Kevincan is a 780 scorer and a kaplan instructor and he advice to forget about it



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