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zelilmaze
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In the xy plane, a circle's center is orign and radius is 5. 08 Sep 2006, 01:50
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In the xy plane, a circle's center is orign and radius is 5. Points x (5,0) and y lie on the circle, what is the distance between x and y?

I) Abscissa of y is 3

II) Ordinate of y is 4



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In the xy plane, a circle's center is orign and radius is 5. 08 Sep 2006, 12:19
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Answer is C


We need both the absicca and the ordinate for the point y to decide the distance between them...
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In the xy plane, a circle's center is orign and radius is 5. 08 Sep 2006, 12:39
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I get (A),

Since X(5,0) is on X axe and on the circle
and Y(a,b) on the circle

(1) Abcissa of Y is 3: means that Y could be (3,b) or (3,-b).

These 2 points are symetrical to the X axe. Thus, the distance of this 2 points to the point X is the same. SUFF

(2) Ordinate of y is 4: This time, Y could be also 2 points (a,4) or (-a,4).

But, these points are symetrical to Y axe. Hence, it remains 2 possible distances to the point X. INSUFF.
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In the xy plane, a circle's center is orign and radius is 5. 08 Sep 2006, 12:43
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Straight A

In statement 1 Y is either (3,b) or (3,-b). Distance from (5,0) is same in both cases.
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haas_mba07
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In the xy plane, a circle's center is orign and radius is 5. 08 Sep 2006, 13:22
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X = (5,0)

S1: Given other point is (3, m) where m is another point on the circle.

As eqn of circle is
x^2 + y^2 = 25

i.e. x = +4, or -4

Y = (3, 4) or (3, -4)
Distance is same in both cases.
Sufficient.

S2: Given y = 4,

x = -3 or +3

Y = (-3, 4) or (3, 4) in which case the distance is different.

Not sufficient.

Answer: A



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