MBAlad
(Edited) Don completes a car journey totalling x miles. During 5 miles of the journey his average speed is 30 miles per hour. For the rest of the journey his average speed is 60 miles per hour. His travel time for the x mile trip is what percent greater than if he'd travelled the whole distance at 60 miles per hour.
a) 8.5%
b) 50%
c) (x/12)%
d) (60/x)%
e) (500/x)%
Folks, I don't find this tough.
Use the loophole of the given problem.
Clearly the answer is dependent on x. So options a and b are out.
Any way what i say here is take a value for x and proceed.
Let's take x= 20.
Initially 5 miles is travelled with 30mph. So time taken is 5/30 = 1/6 of hour = 10 minutes.
Remaining 15 is travelled with 60mph. So time taken is 15/60 = 1/4 of hour = 15 minutes.
So total time taken is 25 minutes.
In the second case entire 20 is travelled with 60 mph.
So time taken is 20/60 = 1/3 of hour = 20 minutes.
So times taken are 20 and 25 minutes respectively.
Clearly time taken in the first case is 25% more than the later case.
Now placing x=20, option E gives us 25%.
So the answer is E.
Is this clear?
Regards,