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yezz
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modules 22 Oct 2006, 14:38
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solve for x

/6+x/ = 2x+1



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Fig
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modules 22 Oct 2006, 15:15
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|6+x| = 2x+1

o If x>-6, |6+x|=6+x
=> 6+x = 2x+1
<=> x = 5

o If x<-6, |6+x|=-x-6
=> -6-x = 2x+1
<=> 3*x = -7
<=> x= -7/3
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iced_tea
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modules 22 Oct 2006, 15:52
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Fig
|6+x| = 2x+1

o If x>-6, |6+x|=6+x
=> 6+x = 2x+1
<=> x = 5

o If x<-6, |6+x|=-x-6
=> -6-x = 2x+1
<=> 3*x = -7
<=> x= -7/3
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i believe this equation has only one solution x = 5

|6+x| >= 0
2x + 1 >= 0 or x >= -1/2
hence x cannot be -7/3

and if you substitute x = -7/3 in the original equation, it won't hold.
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ishtmeet
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modules 22 Oct 2006, 16:41
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Can anyone explain how did you guys figure out from this equation |6+x|=2x+1 that |6+x| >=0 and carried on with the solution????
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Fig
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modules 22 Oct 2006, 23:12
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iced_tea
Fig
|6+x| = 2x+1

o If x>-6, |6+x|=6+x
=> 6+x = 2x+1
<=> x = 5

o If x<-6, |6+x|=-x-6
=> -6-x = 2x+1
<=> 3*x = -7
<=> x= -7/3

i believe this equation has only one solution x = 5

|6+x| >= 0
2x + 1 >= 0 or x >= -1/2
hence x cannot be -7/3

and if you substitute x = -7/3 in the original equation, it won't hold.
Show more


Yes :)... The second one is out :) We have to check back in the original equation as u did :)
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iced_tea
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modules 23 Oct 2006, 17:01
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[quote="ishtmeet"]Can anyone explain how did you guys figure out from this equation |6+x|=2x+1 that |6+x| >=0 and carried on with the solution????[/quot

an absolute value can never be negative.



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!