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28 Dec 2006, 00:16
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If y is an integer, y=|x|+x, is y=0?
1)x<0
2)y<1
1)x<0
2)y<1
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28 Dec 2006, 01:51
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I must pick A....
If x is less than 0 then you take any value and you will get y=0
x=-0.5
0.5-0.5=0
x=-1.8
1.8-1.8=0.....
So on.....
B is obviously not enougth....
If x is less than 0 then you take any value and you will get y=0
x=-0.5
0.5-0.5=0
x=-1.8
1.8-1.8=0.....
So on.....
B is obviously not enougth....
28 Dec 2006, 03:06
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in fact, st2 is sufficient as well so answer is D.
st1 is sufficient as noted above:
if x<0 then |x|=-x
so y=|x|+x = -x+x = 0
suff.
st2 is sufficient as well:
from stem only we can deduce that y is non-negative:
if x<0 then y=0 as we showed above,
if x=0 then obviously y=0.
if x>0 then |x|=x and y = 2x > 0
also note that y is an integer (!!!!!!!)
st2 says y<1. the only non-negative integer less than 1 is 0.
so y must be 0.
hence sufficient.
answer is D.
st1 is sufficient as noted above:
if x<0 then |x|=-x
so y=|x|+x = -x+x = 0
suff.
st2 is sufficient as well:
from stem only we can deduce that y is non-negative:
if x<0 then y=0 as we showed above,
if x=0 then obviously y=0.
if x>0 then |x|=x and y = 2x > 0
also note that y is an integer (!!!!!!!)
st2 says y<1. the only non-negative integer less than 1 is 0.
so y must be 0.
hence sufficient.
answer is D.
