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Bunuel
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imeanup
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arup1590
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roshaun25
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Can you explain where you got 5/18 from?
imeanup
Let's say that the length of first train be \(T_1 = 64 \times \dfrac{5}{18} \times 5 \) meters

and, the length of the second train be \(T_2 = 96 \times \dfrac{5}{18} \times 6\) meters

Therefore, total time taken to cross each other running in the opposite direction is



\(T_{Total} = \dfrac{64 \times 5 + 96 \times 6}{64+96} = \dfrac{896}{160} = 5 \frac{3}{5}\) sec

ANS C
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roshaun25
Can you explain where you got 5/18 from?


5/18 comes from converting km per hour to meters per second.

1 km = 1000 m and 1 hour = 3600 s, so

1 km/hr = 1000/3600 m/s = 5/18 m/s.

Hope it helps.
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the time taken to cross each other =(summation of the lengths of the two trains) / (summation of the speeds of the two trains)
since calculation of both the values in the numerator and the denominator will require multiplication by the same factor of 5/18
hence its not advisable to convert the speeds in m/sec, rather the requisite time can be calculated directly as:
(64*5+96*6)/(64+96)=5 whole 3/5
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