(E) for me too
Is |x-y|>|x| - |y| ?
From 1
y < x
<=> x - y > 0
So, |x-y| = x - y
Then, I will try to find all cases to eliminate the absolute values from the right side of the inequality.
If 0 < y < x then,
o |x| - |y| = x - y = |x-y|
If y < 0 < x then,
o |x| - |y| = x - (-y) = x + y
and
o x + y < x - y as y < 0
So,
o |x| - |y| = x + y < x - y = |x-y|
If y < x < 0 then,
o |x| - |y| = -x - (-y) = y - x
and
o y-x < 0 < x-y (Condition of stat 1)
Thus,
|x| - |y| < |x-y|
Finally,
o If 0 < y < x, then |x| - |y| = |x-y|
o If y < 0 and y < x, then |x| - |y| < |x-y|
INSUFF.
From 2
x*y > 0
Implies:
o x > 0 and y > 0
or
o x < 0 and y < 0
the cases analysed from 1 are still existing here:
o If 0 < y < x, then |x| - |y| = |x-y|
o If y < 0 and y < x, then |x| - |y| < |x-y|
INSUFF.
From (1) and (2):
We remain with the same cases.
INSUFF.