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20 Jun 2007, 19:41
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Which has the greatest value
1. 1/( 3 ^2 * 5 ^2)
2. 2 / ( 3 ^2 * 5 ^2)
3. 7/ (3^3 * 5 ^2)
4. 45/ (3^3 * 5^3)
5. 75/(3^4 * 5 ^5)
1. 1/( 3 ^2 * 5 ^2)
2. 2 / ( 3 ^2 * 5 ^2)
3. 7/ (3^3 * 5 ^2)
4. 45/ (3^3 * 5^3)
5. 75/(3^4 * 5 ^5)
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20 Jun 2007, 20:09
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bewakoof
make the denomenator equal to the highest denomenotor (3^4 x 5^5):
a = (3^2 x 5^3) / (3^4 x 5^5)
b = (2 x 3^2 x 5^3) / (3^4 x 5^5)
c = (7 x 3 x 5^3) / (3^4 x 5^5)
d = (3^3 x 5^3) /(3^4 x 5^5)
e = (3 x 5^2) / (3^4 * 5 ^5)
so the highest is D (3^3 x 5^3) /(3^4 x 5^5).
22 Jun 2007, 16:49
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Simplifying choices C,D and E:
C. 7/ (3^3 * 5 ^2)
-----------------------
if the numerator is 6, then the value is 2/(3^2 * 5^2). So the value of option C is barely higher than the value of B
D. 45/ (3^3 * 5^3)
------------------------
= 3*3*5/(3^3*5^3) = 3/(3^2 * 5^2)
E. 75/(3^4 * 5 ^5)
------------------------
= 3*5*5/(3^4 * 5^5) = 1/(3^3 * 5^2), which is much smaller by a factor of at least 1/3 than all other choices.
ANSWER: D
C. 7/ (3^3 * 5 ^2)
-----------------------
if the numerator is 6, then the value is 2/(3^2 * 5^2). So the value of option C is barely higher than the value of B
D. 45/ (3^3 * 5^3)
------------------------
= 3*3*5/(3^3*5^3) = 3/(3^2 * 5^2)
E. 75/(3^4 * 5 ^5)
------------------------
= 3*5*5/(3^4 * 5^5) = 1/(3^3 * 5^2), which is much smaller by a factor of at least 1/3 than all other choices.
ANSWER: D
