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salr15
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gowani
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salr15
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KillerSquirrel
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Excellent work salr15. you get my two golden stars !

:rotate

here is a good question, not on SD but still very much related:

Set X has 5 numbers, thier average is greater than their median. Set Y has 7 numbers, their average is greater than their median also. If the 2 sets have no common number and are combined to a new set, is the average of the new set greater than its median?

(A) The average of Y is greater than the average of X
(B) The median of Y is greater than the median of X

:-D
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ian7777
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We have a free Standard Deviation lesson on our website. I think it's really good and you all should check it out.

https://www.integratedlearning.net/gmat/sample.asp

Feel free to post comments, as well. We're always trying to improve :-D
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baer
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KillerSquirrel

Set X has 5 numbers, thier average is greater than their median. Set Y has 7 numbers, their average is greater than their median also. If the 2 sets have no common number and are combined to a new set, is the average of the new set greater than its median?

(A) The average of Y is greater than the average of X
(B) The median of Y is greater than the median of X


My head was spinning on this question: I'll go with E though. Rarely do combined sets yield information if there are no bounds for each set. Do you have a simple solution to the above?
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r019h
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KillerSquirrel
Excellent work salr15. you get my two golden stars !

:rotate

here is a good question, not on SD but still very much related:

Set X has 5 numbers, thier average is greater than their median. Set Y has 7 numbers, their average is greater than their median also. If the 2 sets have no common number and are combined to a new set, is the average of the new set greater than its median?

(A) The average of Y is greater than the average of X
(B) The median of Y is greater than the median of X

:-D


seems like E but also seems like E might be wrong.
what's the solution, killersquirrel?
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KillerSquirrel
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The answer is indeed (E)

:-D



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