If x=3/4 and y=1/5, what is the value of sqrt(x^2 + 6x + 9)

Question

If x=3/4 and y=1/5, what is the value of sqrt(x^2 + 6x + 9) - sqrt(y^2 - 2y + 1) ? 

(a)91/20 
(b)59/20 
(c)47/20 
(d)15/4 
(e)14/5 

Please support your answer with explanations

Fig · Answer

(B) for me

sqrt(x^2 + 6x + 9) - sqrt(y^2 - 2y + 1) = sqrt((x+3)^2) - sqrt((y-1)^2) = |x+3| - |y-1| = |3/4 + 3| - |1/5-1| = 15/4 - 4/5 = ((15*5) - 4*4) / 20 = (75-16)/20 = 59/20

shmegs · Answer

B for me as well. Fig's explanation is better than mine, but it works out to be (x+3)-(y+1) = (15/4)-(4/5) = (75/20)-(16/20) = 59/20

ajay_gmat · Answer

OA is B. 

Fig, you mean to say that for all such questions the rule applies..

E.g. sqrt((-3/5)^2) = 3/5 and not -3/5 ??

Am i getting it correct

Fig · Answer

Yes

.... The result of a sqrt() must be positive or 0. So, we cannot have for instance : sqrt(something) = - 4 (In the GMAT limits of course

).

FN · Answer

wow..Figs explanation is awsome..i did it the super long way...

but I get b after 2:30 minutes..Figs approach reduces this to less than 1 minute ...

If x=3/4 and y=1/5, what is the value of sqrt(x^2 + 6x + 9) - sqrt(y^2 - 2y + 1)

well x^2=9/16 x=9/2

so 9/16+9/2+9 well

i multiplied it by 16/16 so I get; 9/16+(9.8)/16 + (9.16)/16

which reduced to (9(1+8+16))/16 or (9.25)/16 so sqrt[(9.25)/16]=3.5/4

same thing with y=1/25-2/5+1

multiply by 25/25 you get 1/25-10/25+25/25= (1-10+25)/25=16/25

sqrt(16/25)=4/5

15/4-4/5= 59/20

B

Gotta luv Figs approach..

ywilfred · Answer

sqrt(9/16 + 18/4 + 9) - sqrt(1/25 - 2/5 + 1)
sqrt(225/16) - sqrt(16/25)
15/4 - 4/5 = 59/20

ajay_gmat · Answer

Hi Fig,

Still having difficulty with thesqrt() being a positive result approach.

How do we then solve for x^2 = 1 ?

For solving this, we do Sqrt(x^2) = sqrt(1).. Hence here x should be only 1 and not x = -1,1 ??

Help..

Fig · Answer

Have a look here on the whole approach to solve it

x^2 = 1 <=> Sqrt(x^2) = sqrt(1) >>>> we can use sqrt() to solve because x^2 >= 0

<=> |x| = |1| <=> |x| = 1 That implies o If x > 0, then x = 1 or o If x < 0, then -x = 1 <=> x = -1 Hope that helps

ajay_gmat · Answer

Thanks Fig.. :-D

Your explanation helped.. The reasoning behind putting the absolute symbol || is to get a positive number always. There can be mutiple values for x.. But |x-1| will always be positive.. :-D

Fig · Answer

Note also that: x^2 = 1 x^2 - 1 = 0 (x+1)*(x-1) = 0 x=-1 or x=1 Another approach in order to avoid a deep undertsanding of what are the tricks behind sqrt(x) and x^2 functions

... Finally not a so good idea?

In short : o sqrt(x) = 1 => x = 1 as a the square root function is only definied for x >=0. o x^2 = 1 => x=-1 or x=1 as the square function is definied for all x and is symetrical to the Y-axis ((-x)^2 = (-1)*(x)^2 = 1 * (x)^2 = x^2).

If x=3/4 and y=1/5, what is the value of sqrt(x^2 + 6x + 9)

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