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Vlad77
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trancing
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for any given question, the probability of guessing right is 1/5 and the prob of guessing wrong is 0.8 = 4/5
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eschn3am
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Quote:
I think it goes like this:

prob (>= 1 correct) = 1 - prob (0 correct)
= 1 - (0.8^4) = 1 - 256/625 = 369/625=0.59
Answer D

Hope this helps.


that seems awfully complex for the GMAT. If this is meant to be solved without a calculator I feel like there has to be another way to go about this one.
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trancing
for any given question, the probability of guessing right is 1/5 and the prob of guessing wrong is 0.8 = 4/5


and then it is to the 4th power becasue it is out of 4?
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Vlad77
Each question on a multiple-choice test has five equally likely answers. If Nicole guesses randomly on four questions, what is the probability she will answer at least one correctly?
(A) 0.25
(B) 0.74
(C) 0.5
(D) 0.59
(E) 0.8


D.
Prob = 1 - all wrongs
Prob= 1 - (4/5)^4 = 1- 256/625 = 369/625 ~= 375/625 = a bit less than 0.6
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Robin in NC
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trancing
I think it goes like this:

prob (>= 1 correct) = 1 - prob (0 correct)
= 1 - (0.8^4) = 1 - 256/625 = 369/625=0.59
Answer D

Hope this helps.


Help me understand - if 1-0.8^4 gives the right answer, why isn't 0.2^4 the right answer? Which would be .16, not a choice. If there is a .8 probability of getting a wrong answer on any given question, why isn't there a .2 probability of getting a right answer?
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bkk145
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Robin in NC
trancing
I think it goes like this:

prob (>= 1 correct) = 1 - prob (0 correct)
= 1 - (0.8^4) = 1 - 256/625 = 369/625=0.59
Answer D

Hope this helps.

Help me understand - if 1-0.8^4 gives the right answer, why isn't 0.2^4 the right answer? Which would be .16, not a choice. If there is a .8 probability of getting a wrong answer on any given question, why isn't there a .2 probability of getting a right answer?


Because the question ask for "at least".
0.2^4 will give you the probability of getting them all right, which is a possibility, but the possibility of getting "at least" one right is much higher than that.
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Robin in NC
trancing
I think it goes like this:

prob (>= 1 correct) = 1 - prob (0 correct)
= 1 - (0.8^4) = 1 - 256/625 = 369/625=0.59
Answer D

Hope this helps.

Help me understand - if 1-0.8^4 gives the right answer, why isn't 0.2^4 the right answer? Which would be .16, not a choice. If there is a .8 probability of getting a wrong answer on any given question, why isn't there a .2 probability of getting a right answer?


.2^4 = P(all 4 right)
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Each answer has probability of 0.2 to be correct.

So P(correct) = 0.2 and P(!correct) = 0.8

P(4 !correct) = 0.8^4 = 0.4096

P(at least one correct) = 1-0.4096 = 0.59

Ans D
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jdel
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maybe this'll help --- there are 5*5*5*5 = 625 possible sets for four answers (5 possibilities for the first prob, 5 possibilities for the second and so on)

addtionally, there are four wrong answers for each problem - so 4*4*4*4 = 256 represents all possible sets of four answers that are made up of only wrong answers. so - if 256 sets have all wrong answers, all the rest have at least one right answer. 625-256 i s 369

so there are 369 sets that have at least one right answer and 369/625 is the answer -

turning that into decimals without a calc --
369 is just a bit more than half of 625. so it's between 59 and 74. and 74 is nearly 3/4 which must be over 450 (45 is 3/4 of 60)

i hope this helps
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Vlad77
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Thanks :-D



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