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jamesrwrightiii
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 19:51
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This was in response to a quiestion in the MGMAT Q Bank..
I was able to calculate the height..
How do I calculate area of equilaterial triangle once given the height?

Jim



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ggarr
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 19:59
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jamesrwrightiii
This was in response to a quiestion in the MGMAT Q Bank..
I was able to calculate the height..
How do I calculate area of equilaterial triangle once given the height?

Jim
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A=b(h)/2 or you can use the area formula for equilateral triangles:

s^2*((sqrt)3)/(4)
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jamesrwrightiii
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 20:04
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Oops I should have been clearer
How do I calculate a side once given a height!
Sorry tired
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ggarr
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 20:32
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jamesrwrightiii
Oops I should have been clearer
How do I calculate a side once given a height!
Sorry tired
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are we told anything else about the triangle other than its height and it being equilateral?
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jamesrwrightiii
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 20:48
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Actually no..I wish I could post the problem but it's copyrighted by MGMAT..basically it asked you to calculate a line..then they said the length of the line was the height of an equilateral triangle and then asked you to find the area..
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Whatever
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 20:49
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equilateral triangle = 2 triangles 30-60-90 which have the sides 1, sqrt3, 2 where sqrt3 = height
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 20:58
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Whatever
equilateral triangle = 2 triangles 30-60-90 which have the sides 1, sqrt3, 2 where sqrt3 = height
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yep. there you go. forgot all about that. there's your answer!
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jamesrwrightiii
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 21:15
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Ok so let me clear this up..

The height is 13..the height is opposite the 60 degree angle
The side opposite the 30 degree angle is 13/sqrt 3?

To get the area...I multiply 13 *13/ Sqrt 3?

Then take that answer *2 to account for the other "side" of the equilateral?
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 21:24
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Ok so let me clear this up..

The height is 13..the height is opposite the 60 degree angle
The side opposite the 30 degree angle is 13/sqrt 3?

To get the area...I multiply 13 *13/ Sqrt 3?

Then take that answer *2 to account for the other "side" of the equilateral?
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13(sqrt)3 is the base of the 30-60-90 triangle. I'd multiply that by 2 and get the base of the entire equilateral triangle. then use the triangle area formula to solve:

b(h)/2 = 26((sqrt)6)*13/2
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 21:34
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So the base is 26/sqrt 3

That times height (26/sqrt3)*13/2

I think what you can do is halve the 26 to account for dividing by 2 so you can..

13*13/sqrt 3=169/sqrt 3


That isn't one of the answers:(
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 21:46
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Could you then post the whole Q please, may be there are some restrictions?
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 21:47
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jamesrwrightiii
So the base is 26/sqrt 3

That times height (26/sqrt3)*13/2

I think what you can do is halve the 26 to account for dividing by 2 so you can..

13*13/sqrt 3=169/sqrt 3


That isn't one of the answers:(
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Is 169((sqrt)6) one of the answers?
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GMATBLACKBELT
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This was in response to a quiestion in the MGMAT Q Bank.. I 28 Aug 2007, 21:57
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jamesrwrightiii
This was in response to a quiestion in the MGMAT Q Bank..
I was able to calculate the height..
How do I calculate area of equilaterial triangle once given the height?

Jim
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Which MGMAT question is this? Must be from the GEO Q bank right?
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jamesrwrightiii
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This was in response to a quiestion in the MGMAT Q Bank.. I 29 Aug 2007, 09:47
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Yep from the Geometry Q Bank...I didn't finish the bank yet so I can't get the official explanation..I got 4-5 questions in and I got tired..



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