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29 Aug 2007, 10:24
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How do we solve this question??
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29 Aug 2007, 12:06
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sidbidus
sidbidus
1/(x+y)[10x+20y]=k
10x+20y=kx+ky
10x-kx=ky-20y
x(10-k)=y(k-20)
x/y=(k-20)/(10-k)
we know that x and y as well as k are positive thus x/y>0
now plug the given answers into the equation x/y=(k-20)/(10-k)
but bear in mind that x<y
so it is D or 18 which gives x/y=1/4
29 Aug 2007, 14:50
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Here's what I did. It worked on this occasion, but not sure if it would in others.
(x/(x+y))10+(y/(x+y))20=k
(10x/(x+y)) + 20y/((x+y))=k
10x+20y/(x+y)=k
10x+20y=k(x+y)
10x+20y=kx+ky
10(x+2y)=kx+ky
So: If x=1, and y>x, let y=2. In this case 2y=2(2)=4
Go back to the simplified equation and plug in 1 and 4 for x and y respectively:
10x+20y/(x+y)=k
10(1)+20(4)/(4+1)=k
10+80/5=18
It seemed much simpler when I was working through it in my head. I wouldn't blame anyone for trying to forget this post.
(x/(x+y))10+(y/(x+y))20=k
(10x/(x+y)) + 20y/((x+y))=k
10x+20y/(x+y)=k
10x+20y=k(x+y)
10x+20y=kx+ky
10(x+2y)=kx+ky
So: If x=1, and y>x, let y=2. In this case 2y=2(2)=4
Go back to the simplified equation and plug in 1 and 4 for x and y respectively:
10x+20y/(x+y)=k
10(1)+20(4)/(4+1)=k
10+80/5=18
It seemed much simpler when I was working through it in my head. I wouldn't blame anyone for trying to forget this post.
