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Q. In a basket, there are 20 red balls, 30 green balls, and 50 white balls. Ten balls are taken from the basket at random. what is the probability that there are 2 red and 4 green balls.
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second attempt ))
p of the concrete outcome is 0,2^2 * 0,3^4 * 0,5^4
Total outcomes we need is 10C2* 8C4 * 4C4 = 10!/(2!*4!*4!)
The ans is p * outcomes =0,064
btw there is difference if the question is at least 2 red and 4 green or exactly - for the first variant p would look as 0,2^2* 0,3^4 *1^4
p of the concrete outcome is 0,2^2 * 0,3^4 * 0,5^4
Total outcomes we need is 10C2* 8C4 * 4C4 = 10!/(2!*4!*4!)
The ans is p * outcomes =0,064
btw there is difference if the question is at least 2 red and 4 green or exactly - for the first variant p would look as 0,2^2* 0,3^4 *1^4
