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abiswas
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KillerSquirrel
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abiswas
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abiswas
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KillerSquirrel, please help me out on this....
I get the number 150/3 - 102/3 = 16....do we have to add 1 to each cause its inclusive?
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ywilfred
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# of terms divisible by 3 --> (150-102)/3 + 1 = 17
# of terms divisible by 5 --> (150-100)/5 + 1 = 11
# of terms divsible by both 5 and 3 --> (150-105)/15 + 1 = 4

Drawing a venn diagram, you can solve for:

# of terms divisible by both 5 and 3 -> 4
# of terms divisible by 3 only -> 13
# of terms divisible by 5 only -> 7

Total = 7+4+13 = 24
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KillerSquirrel
150/3- 102/3 = 16 ---> 17 numbers

150/5-100/5 = 10 ---> 11 numbers

150/15-105/15 = 3 --> 4 numbers

total

17+11-4 = 24 numbers

:)


Are you counting the number of integers that CAN be divided by 3 or by 5?
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ywilfred
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kevincan
KillerSquirrel
150/3- 102/3 = 16 ---> 17 numbers

150/5-100/5 = 10 ---> 11 numbers

150/15-105/15 = 3 --> 4 numbers

total

17+11-4 = 24 numbers

:)

Are you counting the number of integers that CAN be divided by 3 or by 5?

Haha... read it wrong =)

Answer should be ((150-100)+1)-24 = 27 =)
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ywilfred
kevincan
KillerSquirrel
150/3- 102/3 = 16 ---> 17 numbers

150/5-100/5 = 10 ---> 11 numbers

150/15-105/15 = 3 --> 4 numbers

total

17+11-4 = 24 numbers

:)

Are you counting the number of integers that CAN be divided by 3 or by 5?
Haha... read it wrong =)

Answer should be ((150-100)+1)-24 = 27 =)


Yes ! I also fell to that trap.

:?



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