Bunuel
Official Solution:
There are three lamps in a hall. Each lamp can be turned on or off independently. How many different ways can we light up the hall? (Note: The hall is considered lit if at least one lamp is on.)
A. 5
B. 6
C. 7
D. 8
E. 9
Each lamp has two possible states: ON or OFF. Therefore, there are \(2*2*2 = 8\) potential combinations. However, since the case where all lamps are off is not considered a valid illumination, we subtract one, resulting in 7 valid ways to light up the hall.
Answer: C
Bunuel, how can I be sure that the order does not matter in this case? Given that the lamps are in different places, if Lamp 1 is ON and Lamps 2 and 3 are off, it is a different way of lighting the room than Lamp 2 ON and lamp 3 and 1 off.
Thanks
The order in which the lamps are lit does matter, and this is accounted for in the solution. The 8 combinations represent all possible ways to light the 3 lamps:
The last combination, where all lamps are off, is not valid for lighting the hall, leaving 7 valid ways to light it.
Hope it's clear.