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Balvinder
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A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What 27 Oct 2007, 06:54
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36.A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What is the probability that point P(x,y) is within the square? where x^2+y^2=1.



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A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What 27 Oct 2007, 07:31
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Balvinder
36.A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What is the probability that point P(x,y) is within the square? where x^2+y^2=1.
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question is slightly confusing....y u mentioned equaion of a circle x^2+y^2=1

If i were to just consider square..........Probability of point inside square is simply 1/2
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A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What 27 Oct 2007, 11:13
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Agree............The probability should be 100%

x^2 + y ^2 = 1 is equation of a circle with radius 1 and center(0,0). So there is no value os x or y which is greater that 1
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A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What 27 Oct 2007, 11:52
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its a 2x2 square, area = 4, origin at 0

circle, area = pi r^2 = pi(1)^2 = pi

4 > pi so 100%
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A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What 28 Oct 2007, 10:44
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its a 2x2 square, area = 4, origin at 0

circle, area = pi r^2 = pi(1)^2 = pi

4 > pi so 100%
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I get the answer 1 as well. However, what happens if within the square means strictly within the square (as in values where the circle meets the square would become invalid because they would fall on the sqr). Could it be possible?
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A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What 28 Oct 2007, 10:52
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Balvinder
36.A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What is the probability that point P(x,y) is within the square? where x^2+y^2=1.
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i would say the prob is not 100%.

circle is larger than the square.

side of the square = sqrt (1+1) = sqrt2
area of the square = sqrt2 x sqrt2 = 2
area of the circle = pi r^2 = pi

so the probability = 2/pi
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A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What 28 Oct 2007, 11:02
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Balvinder
36.A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What is the probability that point P(x,y) is within the square? where x^2+y^2=1.

i would say the prob is not 100%.

circle is larger than the square.

side of the square = sqrt (1+1) = sqrt2
area of the square = sqrt2 x sqrt2 = 2
area of the circle = pi r^2 = pi

so the probability = 2/pi
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one thing that's confusing is from the coordinates of the square though each side seems to be 2 units each whereas ur calculation pegs the sides at sqrt 2.. how is it possible... I agree that you are right.. but am just not able to figure out where I am wrong!!!
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A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What 28 Oct 2007, 11:47
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dwivedys
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Balvinder
36.A square with points (1,1),(-1,1),(-1,-1)&(1,-1). What is the probability that point P(x,y) is within the square? where x^2+y^2=1.

i would say the prob is not 100%.

circle is larger than the square.

side of the square = sqrt (1+1) = sqrt2
area of the square = sqrt2 x sqrt2 = 2
area of the circle = pi r^2 = pi

so the probability = 2/pi

one thing that's confusing is from the coordinates of the square though each side seems to be 2 units each whereas ur calculation pegs the sides at sqrt 2.. how is it possible... I agree that you are right.. but am just not able to figure out where I am wrong!!!
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in fact, i had a worng impression that (1, 1) is (0, 1). now i agree with you all that it is 100%.



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