Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2512:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
26 Feb 2008, 05:44
Kudos
Bookmarks
Please help me understand this issue. thanks
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
26 Feb 2008, 06:07
Kudos
Bookmarks
Hi alimad,
Since the triangle is equilateral then his angles are 60 degrees each. The small right triangle formed from the side of the square, base and one of the sides of the triangle is then solvable.
Since the upper side of the square is parallel to the base then the triangle formed at the top is also equilateral with side 12. the perimeter of the triangle is (12+8sqrt3)*3
Since the triangle is equilateral then his angles are 60 degrees each. The small right triangle formed from the side of the square, base and one of the sides of the triangle is then solvable.
Since the upper side of the square is parallel to the base then the triangle formed at the top is also equilateral with side 12. the perimeter of the triangle is (12+8sqrt3)*3
26 Feb 2008, 07:00
Kudos
Bookmarks
Each side of the square = 12
Each corner of the large triangle = 60
Using this information we see that the part of the triangle above the square is equilateral as well, so 12-12-12 triangle.
Then we can see that the triangle on each side of the square is a 30-60-90 triangle so the sides are 1-1(sqrt3)-2. We're given the longer leg (12) so we can solve from there.
It's really a long and boring process and I doubt you'd see something with this many steps on the real test (but I could be wrong).
and I get answer D when it's all said and done
Each corner of the large triangle = 60
Using this information we see that the part of the triangle above the square is equilateral as well, so 12-12-12 triangle.
Then we can see that the triangle on each side of the square is a 30-60-90 triangle so the sides are 1-1(sqrt3)-2. We're given the longer leg (12) so we can solve from there.
It's really a long and boring process and I doubt you'd see something with this many steps on the real test (but I could be wrong).
and I get answer D when it's all said and done
