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suntaurian
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Is x \gt 3 ? 1. (x-3)(x-2)(x-1) \gt 03 Mar 2008, 01:15
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Is \(x \gt 3\) ?

1. \((x-3)(x-2)(x-1) \gt 0\)
2. \(x \gt 1\)



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Is x \gt 3 ? 1. (x-3)(x-2)(x-1) \gt 03 Mar 2008, 01:27
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A


(x-3)(x-2)(x-1) >0 -> minimum value of x has to be 4 to satisfy > 0 condition
thus sufficient
x > 1 -> x could be 2,3,4 thus insufficient
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Is x \gt 3 ? 1. (x-3)(x-2)(x-1) \gt 03 Mar 2008, 21:10
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Its E

Even 1.5 satisfies the equation.
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Is x \gt 3 ? 1. (x-3)(x-2)(x-1) \gt 03 Mar 2008, 21:18
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suntaurian
Is \(x \gt 3\) ?

1. \((x-3)(x-2)(x-1) \gt 0\)
2. \(x \gt 1\)
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thats E. x could be any value >1 but <2. so it could or could not be >3.
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Is x \gt 3 ? 1. (x-3)(x-2)(x-1) \gt 04 Mar 2008, 09:19
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prasannar
A


(x-3)(x-2)(x-1) >0 -> minimum value of x has to be 4 to satisfy > 0 condition
thus sufficient
x > 1 -> x could be 2,3,4 thus insufficient
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Try 1.5. This is tricky. U have to remember to try non integer values.


E
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Is x \gt 3 ? 1. (x-3)(x-2)(x-1) \gt 04 Mar 2008, 16:17
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GMATBLACKBELT
prasannar
A


(x-3)(x-2)(x-1) >0 -> minimum value of x has to be 4 to satisfy > 0 condition
thus sufficient
x > 1 -> x could be 2,3,4 thus insufficient

Try 1.5. This is tricky. U have to remember to try non integer values.


E
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Thats exactly where I got dinged. Didn't even think abt the non-integer values.
+1 for being smart :)

OA is E.
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Is x \gt 3 ? 1. (x-3)(x-2)(x-1) \gt 04 Mar 2008, 19:02
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GMATBLACKBELT
prasannar
A


(x-3)(x-2)(x-1) >0 -> minimum value of x has to be 4 to satisfy > 0 condition
thus sufficient
x > 1 -> x could be 2,3,4 thus insufficient

Try 1.5. This is tricky. U have to remember to try non integer values.


E
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I got E as well. but here is my reasoning. Is there anything wrong with the way i look at it.

1. (x-3)(x-2)(x-1) >0
from here x >3, and X>2, and x>1 all 3 options are valid so insufficient.

2. clearly insufficient.

both combined dont give us anything different.
so here i am with E.

Is it wrong to look at (1) the way i look at it? thanks
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Is x \gt 3 ? 1. (x-3)(x-2)(x-1) \gt 04 Mar 2008, 20:53
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elmagnifico
GMATBLACKBELT
prasannar
A


(x-3)(x-2)(x-1) >0 -> minimum value of x has to be 4 to satisfy > 0 condition
thus sufficient
x > 1 -> x could be 2,3,4 thus insufficient

Try 1.5. This is tricky. U have to remember to try non integer values.


E

I got E as well. but here is my reasoning. Is there anything wrong with the way i look at it.

1. (x-3)(x-2)(x-1) >0
from here x >3, and X>2, and x>1 all 3 options are valid so insufficient.

2. clearly insufficient.

both combined dont give us anything different.
so here i am with E.

Is it wrong to look at (1) the way i look at it? thanks
Show more

Took the same approach and arrived at E
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Is x \gt 3 ? 1. (x-3)(x-2)(x-1) \gt 08 Mar 2008, 01:12
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I keep making the same mistake :wall



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