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23 Mar 2008, 08:52
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A list contains 11 consecutive integers. what is the greatest integer on the list?
1) If x is the smallest integer on the list, then (x+72)^1/3=4
2) If x is the smallest integer on the list, and y is the greatest integer on the list,
then 16x^-2=y^-2
Tnx
1) If x is the smallest integer on the list, then (x+72)^1/3=4
2) If x is the smallest integer on the list, and y is the greatest integer on the list,
then 16x^-2=y^-2
Tnx
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23 Mar 2008, 09:35
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Given that list is of 11 consecutive integers. So knowing any terms (provided you know its position in the series), should be enough to tell you the remaining integers in the series.
Statement 1:
Tells us smallest integer, so we should be able to calculate the largest integer of the series. So this statement alone is sufficient.
Mathematically
(x+72) = 4^3 => x+72 = 64 => x = 8
Statement 2:
Tells us about relation between smallest and largest integer. Such relations can be satisfied by infinite possibilities. So this statement alone is not sufficient.
Mathematically
x^2 = 16y^2 or x = +4y or -4y
As x is the smallest number so it cannot be equal to +4y. So x = -4y
First of all this equation can be satisfied by infinite possibilities. Second there is no value of y for which value of x is such that there is 9 consecutive terms in between x & y (because series is 11 consecutive integers).
Answer A.
Statement 1:
Tells us smallest integer, so we should be able to calculate the largest integer of the series. So this statement alone is sufficient.
Mathematically
(x+72) = 4^3 => x+72 = 64 => x = 8
Statement 2:
Tells us about relation between smallest and largest integer. Such relations can be satisfied by infinite possibilities. So this statement alone is not sufficient.
Mathematically
x^2 = 16y^2 or x = +4y or -4y
As x is the smallest number so it cannot be equal to +4y. So x = -4y
First of all this equation can be satisfied by infinite possibilities. Second there is no value of y for which value of x is such that there is 9 consecutive terms in between x & y (because series is 11 consecutive integers).
Answer A.
