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24 May 2008, 16:06
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Man, I hate these types of problems and I don't know why. Anyway,
is |x| = y - z ?
(1) x + y = z
(2) x < 0
I did a rephrase of is x = y - z when x is positive AND is x = z - y when x is negative. I'm not even sure if this rephrase is correct and I don't really know where to go from here or how to attack these problems in the future. Any explanation would be greatly appreciated. Thanks in advance.
is |x| = y - z ?
(1) x + y = z
(2) x < 0
I did a rephrase of is x = y - z when x is positive AND is x = z - y when x is negative. I'm not even sure if this rephrase is correct and I don't really know where to go from here or how to attack these problems in the future. Any explanation would be greatly appreciated. Thanks in advance.
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24 May 2008, 16:59
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brokerbevo
The question is asking is Y > Z
statement 1: we don't know the value of x, so insuff
statement 2: we don't know y or z, insuff
together: if x is negative, then x + y is taking something away from y, and x + y = z, therefore y is greater than z
C
Updated on: 13 Jul 2010, 13:09
Originally posted by TheGMATDoctor on 25 May 2008, 18:50.
Last edited by TheGMATDoctor on 13 Jul 2010, 13:09, edited 1 time in total.
Last edited by TheGMATDoctor on 13 Jul 2010, 13:09, edited 1 time in total.
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Rather, the question is asking: is Y greater or equal to Z assuming there is an equality between x and y-z (or z-y).
Remember the definition of |x|. |x| is always greater or equal to 0.
If x > 0, then |x| = x.
If x = 0 then |x| = 0.
If x < 0, the |x| = -X. Since x < 0, we have to take -X to make it > 0.
So is |x| = y-z ?
We'll have a definite answer to the question if we have an equality between x and y-z (or z-y) And if we know the sign of x or y-z.
1/ x + y = z
so x = z - y--- Not enough information because we need to know the sign of x or y-z.
2/ x < 0 --- Not enough information because we need a relationship between x and y-z
Together we have both an equality and the sign of x.
so |x| = |z-y| = y-z because x being < 0, so is z-y. z-y < 0 ; therefore |x| = |z- y| = -(z-y) = y-z.
C is the answer.
That's all, folks.
Remember the definition of |x|. |x| is always greater or equal to 0.
If x > 0, then |x| = x.
If x = 0 then |x| = 0.
If x < 0, the |x| = -X. Since x < 0, we have to take -X to make it > 0.
So is |x| = y-z ?
We'll have a definite answer to the question if we have an equality between x and y-z (or z-y) And if we know the sign of x or y-z.
1/ x + y = z
so x = z - y--- Not enough information because we need to know the sign of x or y-z.
2/ x < 0 --- Not enough information because we need a relationship between x and y-z
Together we have both an equality and the sign of x.
so |x| = |z-y| = y-z because x being < 0, so is z-y. z-y < 0 ; therefore |x| = |z- y| = -(z-y) = y-z.
C is the answer.
That's all, folks.
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