If a certain prime number (x) is divided by 5, the first part will have a denominator that is 5, and therefore odd. When it's doubled, like anything doubled, it will be even. The stem says that the "fraction is reduced" and results in an odd number. So that means tht 10 (divided by 5 and doubled = 10) when reduced must be an odd number. The only factors of 10 are 1, 2, 5, and 10. Of those, 1 and 5 are odd.
Since the answer is 2, when the fraction \(\frac{x+4}{5*2}\) is reduced, you get \(\frac{3}{5}\) because you start out wit 2 + 4 / 5*2, or 6 / 10. That can be reduced to 3/5 and the denominator is odd.
gdmat720
Can anyone tell me how does the condition "The denominator of the result is odd" is satisfied??
dzelkas
Can someone help me with the solution for below?
A certain prime X is divided by 5 to get a fraction. Then its numerator is increased by 4 and its denominator doubled, after which the resulting fraction is reduced. The denominator of the result is odd. What is X?
a) 7
b) 5
c) 4
d) 3
e) 2