Come on now, give the explanation. Stating what your answer is doesn't help much.
OK. Figured it out now.
If you have an equilateral triangle inscribed inside a circle, the formula to find the Radius of the circle is:
Radius = \(a\frac{\sqrt{3}}{3}\) where is a is the length of 1 side of the equilateral triangle.
An equilateral triangle is made up of two 30-60-90 triangles, so the sides are in proportion of Base = 1, Height = \(\sqrt{3}\), Hypotnuse = 2.
So the equation is:
\(x * x\sqrt{3} = 9\sqrt{3}\)
\(x^2\sqrt{3} = 9\sqrt{3}\)
\(x^2 = 9\)
\(x = 3\)
Don't forget that this is only the base of 1 of the 30-60-90 triangles, so double it to get one complete side of the equilateral triangle. 1 side = 6.
Back to the equation to find the Radius of the circumscribed circle:
a = a side, so
\(6 * \frac{\sqrt{3}}{3}\) = \(\frac{6\sqrt{3}}{3}\) = \(\2\sqrt{3}\)
This is the radius so the area of the circle = \((2\sqrt{3})^2\pi = 4 * 3 = 12\pi\)
prasannar