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iamcartic
Let the equations be:
y=mx+c and y=ax+b

St1: we get 2 eqs - 5m+c=1 and 5a+b=1 or 5m+c=5a+b nothing can be said about values of m and a from this relation hence insuffic.

st2: c>b doent provide any relation btw m and a.

now combining them since 5m+c=5a+b and c>b then mhas to be less than a thus sufficient.

C is the answer


Good explanation.

Agreed.
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Excellent explanation "iamcartic"
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line n crosses y axis at (0,a)
line p crosses y axis at (0,b)

as per statement 1 both lines pass through (5,1)

slope of line n = (1-a)/5 ------ using slope = (y2 - y1) / (x2 - x1)
slope of line p = (1-b)/5

we have to determine if 1-a < 1-b

as per statement 2 : a > b
multiply by -1 on both sides, the inequality sign will change
-a < -b
add 1 on both sides
1-a < 1-b

Option C
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durgesh... is this an ok way of analysing??? or its not advisable?

its like this .. keep one line(LINE n) fixed at 5,1 and a certain y intercept. then take the other line(line P) and fix one point at 5,1 and y intercept < 1st y intercept.
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ritula
Detailed solution will be appreciated.
Thanks

take line n : y=nx+c
line p : y=px+c1

hence now (1) says (5,1) satisfies above equations =>
1=5n+c
1=5p+c1
5(n-p)=c1-c
not solvable since c>c1 or c<c1
INSUFFI

(2) c>c1 does not help since both are indepedent eqns
(n-p)x=c1-c => x is a variable
INSUFFI

COMBINING (1) and (2):

5(n-p)=c1-c and c>c1 => n<p=> SUFFI
IMO C
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arjtryarjtry
durgesh... is this an ok way of analysing??? or its not advisable?

its like this .. keep one line(LINE n) fixed at 5,1 and a certain y intercept. then take the other line(line P) and fix one point at 5,1 and y intercept < 1st y intercept.

i think its ok.. make sure you use both conditions on xy plane only after eliminating that each statement alone is not suff...



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