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giantSwan
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giantSwan
shouldn't the 2+2 and 3+3 repeat for each die since they are unique?
Yes, 2+2 does not differ form 3+1 (if we consider 3+1 and 1+3 as different options)
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giantSwan
shouldn't the 2+2 and 3+3 repeat for each die since they are unique?

There's only one 2 in each die, therefore only only possibility for 2+2. What
you are doing is the same thing as counting twice 3+1, 3+1.

Does it help to think of it in this way?
What are the chances of getting 2 twice in a row:
(1/6)(1/6)=2/36
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giantSwan
shouldn't the 2+2 and 3+3 repeat for each die since they are unique?
walker
Yes, 2+2 does not differ form 3+1 (if we consider 3+1 and 1+3 as different options)
Nope, I think that they actually differ. 2+2 is ONE of the 36 possibilities. 1+3 and 3+1 are TWO of them

You can write down the 36 possibilities if you want to be sure of that :

{1,1} {2,1} {3,1} {4,1} {5,1} {6,1}
{1,2} {2,2} {3,2} {4,2} {5,2} {6,2}
{1,3} {2,3} {3,3} {4,3} {5,3} {6,3}
{1,4} {2,4} {3,4} {4,4} {5,4} {6,4}
{1,5} {2,5} {3,5} {4,5} {5,5} {6,5}
{1,6} {2,6} {3,6} {4,6} {5,6} {6,6}

(bolded are the possibilities that lead to a sum of 4 or 6, you can verify there are 8 of them)

As said above, answer is 8/36 = 2/9
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Oski
Nope, I think that they actually differ. 2+2 is ONE of the 36 possibilities. 1+3 and 3+1 are TWO of them

They differ if only you consider 2,2 and 1,3 without order, otherwise, 2+2 does not differ form 1+3, because probability for both options is 1/36
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walker
They differ if only you consider 2,2 and 1,3 without order, otherwise, 2+2 does not differ form 1+3, because probability for both options is 1/36
It differs because counting 1+3 and its reverse is not double counting, whereas counting 2+2 and its reverse is.

If you try to count "without order", the events are not equiprobable any more and you cannot apply the formula "number of occurrences of the event / number of total possibilities"
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i got the answer 8/36 .. is that right???
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we are talking about the same thing but in other words :)
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walker
we are talking about the same thing but in other words :)
Yes, I just realized it ;)

But not giantSwam :)
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walker
we are talking about the same thing but in other words :)
Yes, I just realized it ;)

But not giantSwam :)

Thanks, this discussion was very helpful. I understand now.
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2/9

4 : 1+3, 2+2, 3+1 = 3/6x6

6: 1+5, 2+4, 3+3, 4+2, 5+1 = 5/6x6

P of a or b = Pa + Pb = 2/9



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