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02 Jun 2004, 21:53
Kudos
Bookmarks
Hi All,
I am just wondering would it be possible for us to create a list of math short cuts / formulae we need for QUANT?. I feel if we could document most commonly used formulas, concepts tested etc. that would be of great help to everybody. BB, Praet, Anand, Akamai and many others, What do you guys say?. Please let me know. I am posting few I have collected.
Thanks
Praveen
Summation Formula =Number of numbers * (f + l), where number of numbers = f тАУ l + 1
Percent Change = Difference/Original
Rectangular Solid Volume = L*W*H
Cube Volume = S*S*S
Cylinder Volume = Pi * r^2 * h
Surface Area (Combined area of all the surfaces, or faces, of a solid)
Surface Area of Rectangular Solid = 2lw + 2lh + 2wh
Surface Area of a Cube = 6 * (side)^2
Principal + Interest = principal * (1+r)>t, where
Total = Group 1 + Group 2 тАУ Both + Neither
Quadratics
тАв (x + y)2 = x2 + 2xy + y2
тАв (x тАУ y)2 = x2 тАУ 2xy + y2
тАв (x + y)(x тАУ y) = x2 тАУ y2
Number of permutations (different arrangements when order matters) = n!
(n-r)!
Number of combinations (arrangements when order doesnтАЩt matter) = n!
r!(n-r)!
where n = number of objects in the source group
where r = number of objects selected
The length of a given side must be greater than the difference of the other two sides and less than the sum of the other two sides.
I am just wondering would it be possible for us to create a list of math short cuts / formulae we need for QUANT?. I feel if we could document most commonly used formulas, concepts tested etc. that would be of great help to everybody. BB, Praet, Anand, Akamai and many others, What do you guys say?. Please let me know. I am posting few I have collected.
Thanks
Praveen
Summation Formula =Number of numbers * (f + l), where number of numbers = f тАУ l + 1
Percent Change = Difference/Original
Rectangular Solid Volume = L*W*H
Cube Volume = S*S*S
Cylinder Volume = Pi * r^2 * h
Surface Area (Combined area of all the surfaces, or faces, of a solid)
Surface Area of Rectangular Solid = 2lw + 2lh + 2wh
Surface Area of a Cube = 6 * (side)^2
Principal + Interest = principal * (1+r)>t, where
Total = Group 1 + Group 2 тАУ Both + Neither
Quadratics
тАв (x + y)2 = x2 + 2xy + y2
тАв (x тАУ y)2 = x2 тАУ 2xy + y2
тАв (x + y)(x тАУ y) = x2 тАУ y2
Number of permutations (different arrangements when order matters) = n!
(n-r)!
Number of combinations (arrangements when order doesnтАЩt matter) = n!
r!(n-r)!
where n = number of objects in the source group
where r = number of objects selected
The length of a given side must be greater than the difference of the other two sides and less than the sum of the other two sides.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
03 Jun 2004, 01:02
Kudos
Bookmarks
Praveen, you should try to give some background info. on a formula.
just an example:
if r is the radius of a circle , then area of the circle = pi * (r)^2
so here, introduce the variables, no matter how obvious it might be. since many of our members will use this list, we got to be very very clear about what we intend to say.
i might consider making this a sticky post and guys can contribute their collection in here. Though the gmat requires very little knowledge of sophisticated formulas, we can do this project just for the new guys.
Praveen, I will rely on you to take the lead here.
Thanks Praveen
Regards
Praet
just an example:
if r is the radius of a circle , then area of the circle = pi * (r)^2
so here, introduce the variables, no matter how obvious it might be. since many of our members will use this list, we got to be very very clear about what we intend to say.
i might consider making this a sticky post and guys can contribute their collection in here. Though the gmat requires very little knowledge of sophisticated formulas, we can do this project just for the new guys.
Praveen, I will rely on you to take the lead here.
Thanks Praveen
Regards
Praet
Number Properties:
A product of x consecutive integers is always divisible by the numbers 1 through x. (i.e. product any 5 consecutive integers is always divisible by 1,2,3,4, and 5) (i'm pretty sure this holds true in all cases, can someone please double check on this).
sum of any number of consecutive integers = average of high and low integers * #of integers.
divisibility:
divisible by 2 if even
divisible by 3 if sum of digits is a multiple of 3
divisible by 4 if last 2 digits are divisible by 4 (i.e. 152 is divisible by 4 because 52 is divisible by 4). Also can be divided by 2 twice.
divisible by 5 if units digit is 5 or 0
divisible by 6 if divisble by 3 and even
divisible by 7 ??? I have no tricks for this one
divisible by 8 if divisble by 2 three times
divisible by 9 if sum of digits is multiple of 9
divisble by 10 if zero in units digit
divisible by 11 if digits are the same (for 2 digit numbers). if first and last digit adds up to middle digit (for 3 digit numbers. i.e. 121 = 1+1=2 so divisble by 11)
Units digits of x^y:
1^anything = 1
2^(1+4x) = 2, 2^(2+4x) = 4, 2^(3+4x) = 8, 2^(4+4x) = 6
3^(1+3x) = 3, 3^(2+3x) = 9, 2^(3+3x) = 1
4^(1+2x) = 4, 4^(2+2x) = 6
5^anything = 5
6^anything = 6
7^(1+4x) = 7, 7^(2+4x) = 9, 7^(3+4x) = 3, 7^(4+4x) = 1
8^(1+4x) = 8, 8^(2+4x) = 4, 8^(3+4x) = 2, 8^(4+4x) = 6
9^(1+2x) = 9, 9^(2+2x) = 1
0^anything = 0
For any number, look at the units match the units digit to the list above and you can find the units digit of that number raised to anything.
Odds and evens:
O+O = E
O+E = O
E+E = E
O*O = O
O * E = E
E * E = E
Add any x consecutive integers:
If x is even, the sum is odd
If x is odd and the first number in the sequence is odd, the sum is odd
If x is odd and the first number in the sequence is even, the sum is even.
Odd raised to any power is Odd
Even raised to any power is Even
A product of x consecutive integers is always divisible by the numbers 1 through x. (i.e. product any 5 consecutive integers is always divisible by 1,2,3,4, and 5) (i'm pretty sure this holds true in all cases, can someone please double check on this).
sum of any number of consecutive integers = average of high and low integers * #of integers.
divisibility:
divisible by 2 if even
divisible by 3 if sum of digits is a multiple of 3
divisible by 4 if last 2 digits are divisible by 4 (i.e. 152 is divisible by 4 because 52 is divisible by 4). Also can be divided by 2 twice.
divisible by 5 if units digit is 5 or 0
divisible by 6 if divisble by 3 and even
divisible by 7 ??? I have no tricks for this one
divisible by 8 if divisble by 2 three times
divisible by 9 if sum of digits is multiple of 9
divisble by 10 if zero in units digit
divisible by 11 if digits are the same (for 2 digit numbers). if first and last digit adds up to middle digit (for 3 digit numbers. i.e. 121 = 1+1=2 so divisble by 11)
Units digits of x^y:
1^anything = 1
2^(1+4x) = 2, 2^(2+4x) = 4, 2^(3+4x) = 8, 2^(4+4x) = 6
3^(1+3x) = 3, 3^(2+3x) = 9, 2^(3+3x) = 1
4^(1+2x) = 4, 4^(2+2x) = 6
5^anything = 5
6^anything = 6
7^(1+4x) = 7, 7^(2+4x) = 9, 7^(3+4x) = 3, 7^(4+4x) = 1
8^(1+4x) = 8, 8^(2+4x) = 4, 8^(3+4x) = 2, 8^(4+4x) = 6
9^(1+2x) = 9, 9^(2+2x) = 1
0^anything = 0
For any number, look at the units match the units digit to the list above and you can find the units digit of that number raised to anything.
Odds and evens:
O+O = E
O+E = O
E+E = E
O*O = O
O * E = E
E * E = E
Add any x consecutive integers:
If x is even, the sum is odd
If x is odd and the first number in the sequence is odd, the sum is odd
If x is odd and the first number in the sequence is even, the sum is even.
Odd raised to any power is Odd
Even raised to any power is Even
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
